Following code has to be used in the main-function, but I don't know how it is used.
在主函数中必须使用以下代码,但是我不知道如何使用它。
struct SomeItem
{
enum {MOVIE, MUSIC} itemType;
union {
struct Movie* movie;
struct Music* music;
};
};
this struct is used in a dynamic linked list with previous/item/next pointer, but I don't know how you can set the enum. Or how to initialize it.
这个结构体用于具有前/项/下一个指针的动态链表中,但是我不知道如何设置enum。或者如何初始化它。
I need to know how it would look like in the main-function.
我需要知道主函数是怎样的。
biglist.someitem = ???;
/* declaration I use */
struct Library* biglist;
more code to understand what Im trying to do.
更多的代码来理解我要做什么。
struct Library{
struct SomeItem* someitem;
struct SomeItem* previousItem;
struct SomeItem* nextItem;
};
compiler errors: C2037: left of 'someitem' specifies undefined struct/union 'library' C2065: MOVIE: undeclared identifier
编译错误:C2037:“someitem”左边指定未定义的struct/union 'library' C2065: MOVIE: undeclare identifier
Im still a rookie on ANSI C, so dont shoot me ok ;)
我仍然是ANSI C的新手,所以别开枪打我。
4 个解决方案
#1
13
You're using pointers everywhere, so you need to use -> to reference the items.
您使用的指针到处都是,所以您需要使用->来引用这些项。
ie. biglist->someitem->itemType = MOVIE;
ie。biglist - > someitem - > itemType =电影;
The below code compiles fine with gcc -Wall -strict:
下面的代码用gcc -Wall -strict编译好:
struct SomeItem
{
enum {MOVIE, MUSIC} itemType;
union {
struct Movie* movie;
struct Music* music;
} item;
};
struct Library{
struct SomeItem* someitem;
struct SomeItem* previousItem;
struct SomeItem* nextItem;
};
int main(void)
{
struct Library* biglist;
biglist->someitem->itemType = MOVIE;
return 0;
}
(Though this code won't run of course, as I'm not allocating any memory for biglist and someitem!)
(虽然这段代码当然不会运行,因为我没有为biglist和someitem分配任何内存!)
#2
4
biglist.someitem.itemType = MOVIE; /* or = MUSIC */
Or, if someitem
is a pointer,
或者,如果某项是指针,
biglist.someitem->itemType = MOVIE; /* or = MUSIC */
#3
0
You may initialize the enum in such a way biglist->someitem = MOVIE; but the compiler assigns integer values starting from 0. So: biglist->someitem=MOVIE returns 0 or biglist->someitem=MUSIC return 1
您可以以这种方式初始化enum ->someitem = MOVIE;但是编译器从0开始分配整数值。那么:biglist->someitem=MOVIE return 0或biglist->someitem=MUSIC return 1
check if it helps any good,
检查它是否有用,
#4
0
struct SomeItem
{
enum {MOVIE, MUSIC} itemType;
union {
struct Movie* movie;
struct Music* music;
} item;
struct SomeItem *next;
};
#1
13
You're using pointers everywhere, so you need to use -> to reference the items.
您使用的指针到处都是,所以您需要使用->来引用这些项。
ie. biglist->someitem->itemType = MOVIE;
ie。biglist - > someitem - > itemType =电影;
The below code compiles fine with gcc -Wall -strict:
下面的代码用gcc -Wall -strict编译好:
struct SomeItem
{
enum {MOVIE, MUSIC} itemType;
union {
struct Movie* movie;
struct Music* music;
} item;
};
struct Library{
struct SomeItem* someitem;
struct SomeItem* previousItem;
struct SomeItem* nextItem;
};
int main(void)
{
struct Library* biglist;
biglist->someitem->itemType = MOVIE;
return 0;
}
(Though this code won't run of course, as I'm not allocating any memory for biglist and someitem!)
(虽然这段代码当然不会运行,因为我没有为biglist和someitem分配任何内存!)
#2
4
biglist.someitem.itemType = MOVIE; /* or = MUSIC */
Or, if someitem
is a pointer,
或者,如果某项是指针,
biglist.someitem->itemType = MOVIE; /* or = MUSIC */
#3
0
You may initialize the enum in such a way biglist->someitem = MOVIE; but the compiler assigns integer values starting from 0. So: biglist->someitem=MOVIE returns 0 or biglist->someitem=MUSIC return 1
您可以以这种方式初始化enum ->someitem = MOVIE;但是编译器从0开始分配整数值。那么:biglist->someitem=MOVIE return 0或biglist->someitem=MUSIC return 1
check if it helps any good,
检查它是否有用,
#4
0
struct SomeItem
{
enum {MOVIE, MUSIC} itemType;
union {
struct Movie* movie;
struct Music* music;
} item;
struct SomeItem *next;
};