如何转义要在NSURL中使用的NSString？

Got this code so far for my send button:

到目前为止我的发送按钮有这个代码：

NSString* urlString = [NSString stringWithFormat:@"http://server.com/ios/add.php?user=iPhone+App&message=%@", messageBox.text stringByAddingPercentEscapesUsingEncoding : NSUFT8StringEncoding];
NSURL *add = [NSURL URLWithString:urlString];

However I do get the error "Expected ':'

但是我确实收到错误“预期”：'

5 个解决方案

#1

You need to separate the two string construction calls

您需要分开两个字符串构造调用

NSString* urlString = [[NSString stringWithFormat:@"http://server.com/ios/add.php?user=iPhone+App&message=%@", messageBox.text] stringByAddingPercentEscapesUsingEncoding : NSUTF8StringEncoding];
NSURL *add = [NSURL URLWithString:urlString];

#2

The proper way is not to escape the entire URL. You should only escape individual parameter values.

正确的方法是不要逃避整个URL。您应该只转义单个参数值。

NSString* urlString = [NSString stringWithFormat:@"http://server.com/ios/add.php?user=iPhone+App&message=%@", [messageBox.text stringByAddingPercentEscapesUsingEncoding : NSUFT8StringEncoding]];

Better yet, for readability and easier debugging, do this:

更好的是，为了便于阅读和调试，请执行以下操作：

NSString *escapedText = [messageBox.text stringByAddingPercentEscapesUsingEncoding:NSUFT8StringEncoding];
NSString* urlString = [NSString stringWithFormat:@"http://server.com/ios/add.php?user=iPhone+App&message=%@", escapedText];

#3

Try:

尝试：

NSString* urlString = [[NSString stringWithFormat:@"http://server.com/ios/add.php?user=iPhone+App&message=%@", messageBox.text] stringByAddingPercentEscapesUsingEncoding : NSUFT8StringEncoding];

#4

Separate the NSString method to see it clearly:

分离NSString方法以清楚地看到它：

NSString* urlString = [[NSString stringWithFormat:@"http://server.com/ios/add.php?user=iPhone+App&message=%@", messageBox.text] stringByAddingPercentEscapesUsingEncoding : NSUFT8StringEncoding];

#5

NSURL will automatically url encode the string when you call NSURL urlWithString this code is not needed.

当您调用NSURL urlWithString时，NSURL将自动对字符串进行url编码，不需要此代码。