数据框中grep上的布尔运算符

I'm organizing some gatherings, and I've been storing the names and phone extensions in an R dataframe.

我正在组织一些聚会,我一直在R数据帧中存储名称和电话分机。

names <- c("Adrian Xavier", "Berta Xavier",
           "Charles Yamazaki", "Daniela Yamazaki",
           "Edward Zachary", "Fiona Zachary")
phonex <- c(4739, 3894,
            7238, 7459,
            7573, 9457)
people <- data.frame("Name"=names, "PhoneX"=phonex)

To invite the Yamazakis only, I prepare the list by

要仅邀请Yamazakis,我准备列表

only_y <- people[grep("Yamazaki", people$"Name"), ]

and to prepare a list that excludes the same set, I run:

并且为了准备一个排除相同集合的列表,我运行:

exclude_y <- people[grep("Yamazaki", people$"Name", invert=TRUE), ]

How do I prepare a list that excludes both the Xaviers and the Yamazakis, but that includes everyone else?

我如何准备一份排除Xaviers和Yamazakis的名单,但其中包括其他人?

Related questions:

• R grep: is there an AND operator?

R grep:有一个AND运算符吗?

• R — Logical grep on multiple variables within data frame

R - 数据帧内多个变量的逻辑grep

1 个解决方案

#1

Just use the or in your regular expression.

只需在正则表达式中使用或。

people[!grepl("Yamazaki|Xavier", people$Name), ]

            Name PhoneX
5 Edward Zachary   7573
6  Fiona Zachary   9457