在主函数中输入10个字符串(不等长),用另一函数对它们排序,然后在主函数中输出这10个已排好的字符串(指针数组的方法处理)
#include<stdio.h>
#include<stdlib.h>
#define N 11//
void fun(char* str[]) {
char* temp;
for (int i = 0; i < 10; ++i) {
for (int j = i + 1; j < 10; ++j) {
for (int k = 0; k < N; ++k) {
if (str[i][k] > str[j][k]) {
temp = str[i];
str[i] = str[j];
str[j] = temp;
break;
}
else if (str[i][k] < str[j][k]) {
break;
}
}
}
}
}
void main() {
char str1[N] = { '\0' };
char str2[N] = { '\0' };
char str3[N] = { '\0' };
char str4[N] = { '\0' };
char str5[N] = { '\0' };
char str6[N] = { '\0' };
char str7[N] = { '\0' };
char str8[N] = { '\0' };
char str9[N] = { '\0' };
char str10[N] = { '\0' };
//定义指针数组str, 由10个指向char型数据的指针元素组成, 这10个指针元素分别是指向十个字符数组的指针
char* str[10] = { str1,str2,str3,str4,str5,str6,str7,str8,str9,str10 };
for (int i = 0; i < 10; ++i) {
printf("请输入第%d个字符串\n", i + 1);
fgets(str[i], N, stdin);
}
system("cls");
//消除用fgets函数接受字符串后字符串末尾的换行符'\n'
for (int i = 0; i < 10; ++i) {
for (char* p = str[i]; *p; ++p) {
if (*p == '\n') {
*p = '\0';
break;
}
}
}
printf("排序前:\n");
for (int i = 0; i < 10; ++i) {
printf("%s\n\n", str[i]);
}
fun(str);
printf("排序后:\n");
for (int i = 0; i < 10; ++i) {
printf("%s\n\n", str[i]);
}
system("pause");
}
