I've an array.
我一个数组。
Array
(
[initial] => MSS
[hour] => 5.2
[row_checker_1] => 1
[project_name_1] => KGD001
[project_shortcode_1] => KGD001
[5_1] => 23
[6_1] => 3.3
[4_1] => 23.2
[remarks_1] => on going
[task_id] => 76
[row_checker_2] => 2
[project_name_2] => DG001
[project_shortcode_2] => DG001
[5_2] => 1.1
[6_2] => 2.2
[4_2] => 3.1
[remarks_2] => on going
)
Now I want to split all element upper range key is "project_shortcode_1" and lower range key is remarks_1.
现在我要将所有元素的上量程键都拆分为“project_shortcode_1”，下量程键则是娱令1。
So, new array should look like:
因此，新数组应该如下所示:
array
(
[5_1] => 23
[6_1] => 3.3
[4_1] => 23.2
)
4 个解决方案
#1
2
Use array_filter with flag ARRAY_FILTER_USE_KEY for using the array keys, and do the comparison with the logic needed to get the desired keys. It works from PHP 5.6.
使用带有标志ARRAY_FILTER_USE_KEY的array_filter来使用数组键，并与获取所需键所需的逻辑进行比较。它从PHP 5.6开始工作。
$arr = array ( "initial" => "MSS",
"hour" => 5.2,
"row_checker_1" => 1,
"project_name_1" => "KGD001",
"project_shortcode_1" => "KGD001",
"5_1" => 23,
"6_1" => 3.3,
"4_1" => 23.2,
"remarks_1" => "on going",
"task_id" => 76,
"row_checker_2" => 2,
"project_name_2" => "DG001",
"project_shortcode_2" => "DG001",
"5_2" => 1.1,
"6_2" => 2.2,
"4_2" => 3.1,
"remarks_2" => "on going",
);
// PHP > 5.6
$result = array_filter($arr, function($k){
$var = explode('_', $k);
return is_numeric($var[0]) && $var[1]==1;
}, ARRAY_FILTER_USE_KEY);
#2
2
If what you need is a multidimensional array with all the ranges NUMBER_N, then use something like this (extended from Dmitriy Demir answer):
如果您需要的是一个具有所有range NUMBER_N的多维数组，那么使用如下方法(从Dmitriy Demir的答案扩展而来):
$myArray = array(
'initial' => 'MSS',
'hour' => '5.2',
'row_checker_1' => '1',
'project_name_1' => 'KGD001',
'project_shortcode_1' => 'KGD001',
'5_1' => '23',
'6_1' => '3.3',
'4_1' => '23.2',
'remarks_1' => 'on going',
'task_id' => '76',
'row_checker_2' => '2',
'project_name_2' => 'DG001',
'project_shortcode_2' => 'DG001',
'5_2' => '1.1',
'6_2' => '2.2',
'4_2' => '3.1',
'remarks_2' => 'on going'
);
function splitRange($a){
$newArray = array();
foreach ($a as $k => $v) {
$rightFormat = preg_match('/^\d+_(\d+)$/', $k, $index);
if ($rightFormat)
$newArray[$index[1]][$k] = $v;
}
return $newArray;
}
print_r(splitRange($myArray));
The result will be something like:
结果会是:
Array
(
[1] => Array
(
[5_1] => 23
[6_1] => 3.3
[4_1] => 23.2
)
[2] => Array
(
[5_2] => 1.1
[6_2] => 2.2
[4_2] => 3.1
)
)
being N from NUMBER_N the index of the array.
N来自NUMBER_N是数组的索引。
#3
1
Since you mentioned in the comments that you'd prefer to get all values that are in format NUMBER_1 I think you'd need to loop through your array and check the value names with regex, then add the values to a new array if they meet the criteria. Here's how I would do this:
由于您在评论中提到，您希望获得格式为NUMBER_1的所有值，因此我认为您需要对数组进行循环，并使用regex检查值名，然后将这些值添加到一个新的数组中，如果它们满足条件的话。我是这样做的:
$myArray = array(
'initial' => 'MSS',
'hour' => '5.2',
'row_checker_1' => '1',
'project_name_1' => 'KGD001',
'project_shortcode_1' => 'KGD001',
'5_1' => '23',
'6_1' => '3.3',
'4_1' => '23.2',
'remarks_1' => 'on going',
'task_id' => '76',
'row_checker_2' => '2',
'project_name_2' => 'DG001',
'project_shortcode_2' => 'DG001',
'5_2' => '1.1',
'6_2a' => '2.2',
'4_2' => '3.1',
'remarks_2' => 'on going'
);
$newArray = array();
foreach ($myArray as $k => $v) {
$rightFormat = preg_match('/^\d+_\d+$/', $k);
if ($rightFormat)
$newArray[$k] = $v;
}
print_r($newArray);
The result of print_r in that case would be:
在这种情况下，print_r的结果是:
Array ( [5_1] => 23 [6_1] => 3.3 [4_1] => 23.2 [5_2] => 1.1 [6_2] => 2.2 [4_2] => 3.1 )
数组([5 _1]= > 23(6 _1)= > 3.3(4 _1)= 1.1 > 23.2(5 _2)= >[6 _2)= > 2.2(4)_2)= > 3.1)
If the number after the underscore should always be 1 then change the regex from /^\d+_\d+$/ to /^\d+_1$/.
如果强调后面的数字应该是1然后改变正则表达式/ ^ \ d + _ \ d + / / ^ \ d + _1美元/。
You can play around and see how regex works here.
您可以在这里玩一玩，看看regex是如何工作的。
PS: I've set all values to strings out of convenience. Feel free to modify that.
PS:为了方便，我把所有的值都设置成字符串。请随意修改。
#4
1
A regex-based solution seems fitting for this question.
基于regex的解决方案似乎适合这个问题。
preg_grep() is a function designed to apply a regex filter upon each value in an array. I little more tweaking is necessary for this case because the keys must be filtered instead.
preg_grep()是设计用来对数组中的每个值应用regex过滤器的函数。对于这种情况，我只需稍作调整，因为键必须被过滤。
The One-liner:
一行程序:
$output=array_intersect_key($input,array_flip(preg_grep("/^\d+_1$/",array_keys($input)))));
/* array (
'5_1' => 23,
'6_1' => 3.3,
'4_1' => 23.2,
)*/
Here is the step-by-step array manipulation...
下面是一步一步的数组操作……
array_keys($input); // create array with input keys as values
/* array (
0 => 'initial',
1 => 'hour',
2 => 'row_checker_1',
3 => 'project_name_1',
4 => 'project_shortcode_1',
5 => '5_1',
6 => '6_1',
7 => '4_1',
8 => 'remarks_1',
9 => 'task_id',
10 => 'row_checker_2',
11 => 'project_name_2',
12 => 'project_shortcode_2',
13 => '5_2',
14 => '6_2',
15 => '4_2',
16 => 'remarks_2',
) */
preg_grep("/^\d+_1$/",array_keys($input)); // filter the input array using regex pattern
/* array (
5 => '5_1',
6 => '6_1',
7 => '4_1',
) */
array_flip(preg_grep("/^\d+_1$/",array_keys($input))); // flip the filtered array
/* array (
'5_1' => 5,
'6_1' => 6,
'4_1' => 7,
)*/
array_intersect_key($input,array_flip(preg_grep("/^\d+_1$/",array_keys($input)))); // filter input by comparing keys against filtered array
/* array (
'5_1' => 23,
'6_1' => 3.3,
'4_1' => 23.2,
)*/
#1
2
Use array_filter with flag ARRAY_FILTER_USE_KEY for using the array keys, and do the comparison with the logic needed to get the desired keys. It works from PHP 5.6.
使用带有标志ARRAY_FILTER_USE_KEY的array_filter来使用数组键，并与获取所需键所需的逻辑进行比较。它从PHP 5.6开始工作。
$arr = array ( "initial" => "MSS",
"hour" => 5.2,
"row_checker_1" => 1,
"project_name_1" => "KGD001",
"project_shortcode_1" => "KGD001",
"5_1" => 23,
"6_1" => 3.3,
"4_1" => 23.2,
"remarks_1" => "on going",
"task_id" => 76,
"row_checker_2" => 2,
"project_name_2" => "DG001",
"project_shortcode_2" => "DG001",
"5_2" => 1.1,
"6_2" => 2.2,
"4_2" => 3.1,
"remarks_2" => "on going",
);
// PHP > 5.6
$result = array_filter($arr, function($k){
$var = explode('_', $k);
return is_numeric($var[0]) && $var[1]==1;
}, ARRAY_FILTER_USE_KEY);
#2
2
If what you need is a multidimensional array with all the ranges NUMBER_N, then use something like this (extended from Dmitriy Demir answer):
如果您需要的是一个具有所有range NUMBER_N的多维数组，那么使用如下方法(从Dmitriy Demir的答案扩展而来):
$myArray = array(
'initial' => 'MSS',
'hour' => '5.2',
'row_checker_1' => '1',
'project_name_1' => 'KGD001',
'project_shortcode_1' => 'KGD001',
'5_1' => '23',
'6_1' => '3.3',
'4_1' => '23.2',
'remarks_1' => 'on going',
'task_id' => '76',
'row_checker_2' => '2',
'project_name_2' => 'DG001',
'project_shortcode_2' => 'DG001',
'5_2' => '1.1',
'6_2' => '2.2',
'4_2' => '3.1',
'remarks_2' => 'on going'
);
function splitRange($a){
$newArray = array();
foreach ($a as $k => $v) {
$rightFormat = preg_match('/^\d+_(\d+)$/', $k, $index);
if ($rightFormat)
$newArray[$index[1]][$k] = $v;
}
return $newArray;
}
print_r(splitRange($myArray));
The result will be something like:
结果会是:
Array
(
[1] => Array
(
[5_1] => 23
[6_1] => 3.3
[4_1] => 23.2
)
[2] => Array
(
[5_2] => 1.1
[6_2] => 2.2
[4_2] => 3.1
)
)
being N from NUMBER_N the index of the array.
N来自NUMBER_N是数组的索引。
#3
1
Since you mentioned in the comments that you'd prefer to get all values that are in format NUMBER_1 I think you'd need to loop through your array and check the value names with regex, then add the values to a new array if they meet the criteria. Here's how I would do this:
由于您在评论中提到，您希望获得格式为NUMBER_1的所有值，因此我认为您需要对数组进行循环，并使用regex检查值名，然后将这些值添加到一个新的数组中，如果它们满足条件的话。我是这样做的:
$myArray = array(
'initial' => 'MSS',
'hour' => '5.2',
'row_checker_1' => '1',
'project_name_1' => 'KGD001',
'project_shortcode_1' => 'KGD001',
'5_1' => '23',
'6_1' => '3.3',
'4_1' => '23.2',
'remarks_1' => 'on going',
'task_id' => '76',
'row_checker_2' => '2',
'project_name_2' => 'DG001',
'project_shortcode_2' => 'DG001',
'5_2' => '1.1',
'6_2a' => '2.2',
'4_2' => '3.1',
'remarks_2' => 'on going'
);
$newArray = array();
foreach ($myArray as $k => $v) {
$rightFormat = preg_match('/^\d+_\d+$/', $k);
if ($rightFormat)
$newArray[$k] = $v;
}
print_r($newArray);
The result of print_r in that case would be:
在这种情况下，print_r的结果是:
Array ( [5_1] => 23 [6_1] => 3.3 [4_1] => 23.2 [5_2] => 1.1 [6_2] => 2.2 [4_2] => 3.1 )
数组([5 _1]= > 23(6 _1)= > 3.3(4 _1)= 1.1 > 23.2(5 _2)= >[6 _2)= > 2.2(4)_2)= > 3.1)
If the number after the underscore should always be 1 then change the regex from /^\d+_\d+$/ to /^\d+_1$/.
如果强调后面的数字应该是1然后改变正则表达式/ ^ \ d + _ \ d + / / ^ \ d + _1美元/。
You can play around and see how regex works here.
您可以在这里玩一玩，看看regex是如何工作的。
PS: I've set all values to strings out of convenience. Feel free to modify that.
PS:为了方便，我把所有的值都设置成字符串。请随意修改。
#4
1
A regex-based solution seems fitting for this question.
基于regex的解决方案似乎适合这个问题。
preg_grep() is a function designed to apply a regex filter upon each value in an array. I little more tweaking is necessary for this case because the keys must be filtered instead.
preg_grep()是设计用来对数组中的每个值应用regex过滤器的函数。对于这种情况，我只需稍作调整，因为键必须被过滤。
The One-liner:
一行程序:
$output=array_intersect_key($input,array_flip(preg_grep("/^\d+_1$/",array_keys($input)))));
/* array (
'5_1' => 23,
'6_1' => 3.3,
'4_1' => 23.2,
)*/
Here is the step-by-step array manipulation...
下面是一步一步的数组操作……
array_keys($input); // create array with input keys as values
/* array (
0 => 'initial',
1 => 'hour',
2 => 'row_checker_1',
3 => 'project_name_1',
4 => 'project_shortcode_1',
5 => '5_1',
6 => '6_1',
7 => '4_1',
8 => 'remarks_1',
9 => 'task_id',
10 => 'row_checker_2',
11 => 'project_name_2',
12 => 'project_shortcode_2',
13 => '5_2',
14 => '6_2',
15 => '4_2',
16 => 'remarks_2',
) */
preg_grep("/^\d+_1$/",array_keys($input)); // filter the input array using regex pattern
/* array (
5 => '5_1',
6 => '6_1',
7 => '4_1',
) */
array_flip(preg_grep("/^\d+_1$/",array_keys($input))); // flip the filtered array
/* array (
'5_1' => 5,
'6_1' => 6,
'4_1' => 7,
)*/
array_intersect_key($input,array_flip(preg_grep("/^\d+_1$/",array_keys($input)))); // filter input by comparing keys against filtered array
/* array (
'5_1' => 23,
'6_1' => 3.3,
'4_1' => 23.2,
)*/