PHP preg_split有两个分隔符，除非分隔符在引号内

Further on from my previous question about preg_split which was answers super fast, thanks to nick; I would really like to extend the scenario to no split the string when a delimiter is within quotes. For example:

从我之前关于preg_split的问题开始，这个答案超级快，这要归功于尼克;当分隔符在引号内时，我真的想将场景扩展为不拆分字符串。例如：

If I have the string foo = bar AND bar=foo OR foobar="foo bar", I'd wish to split the sting on every space or = character but include the = character in the returned array (which works great currently), but I don't want to split the string either of the delimiters are within quotes.

如果我有串富=酒吧和酒吧= foo的OR = foobar的“富巴”，我想拆就每一个空间或=字符的刺痛，但包括返回数组中的字符=（目前的伟大作品），但是我不想拆分字符串中的任何一个分隔符都在引号内。

I've got this so far:

到目前为止我有这个：

<!doctype html>
<?php

$string = 'foo = bar AND bar=foo';

$array = preg_split('/ +|(=)/', $string, -1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);

?>
<pre>
<?php

print_r($array);

?>
</pre>

Which gets me:

哪个让我：

Array
(
    [0] => foo
    [1] => =
    [2] => bar
    [3] => AND
    [4] => bar
    [5] => =
    [6] => foo
)

But if I changed the string to:

但是，如果我将字符串更改为：

$string = 'foo = bar AND bar=foo OR foobar = "foo bar"';

I'd really like the array to be:

我真的很喜欢这个数组：

Array
(
    [0] => foo
    [1] => =
    [2] => bar
    [3] => AND
    [4] => bar
    [5] => =
    [6] => foo
    [6] => OR
    [6] => foobar
    [6] => =
    [6] => "foo bar"
)

Notice the "foo bar" wasn't split on the space because it's in quotes?

请注意，“foo bar”没有在空格上拆分，因为它在引号中？

Really not sure how to do this within the RegEx or if there is even a better way but all your help would be very much appreciated!

真的不知道如何在RegEx中做到这一点，或者如果有更好的方法，但所有的帮助将非常感谢！

Thank you all in advance!

谢谢大家！

3 个解决方案

#1

I was able to do this by adding quoted strings as a delimiter a-la

我能够通过添加带引号的字符串作为分隔符a-la来完成此操作

"(.*?)"| +|(=)

The quoted part will be captured. It seems like this is a bit tenuous and I did not test it extensively, but it at least works on your example.

引用的部分将被捕获。这似乎有点脆弱，我没有广泛测试它，但它至少适用于你的例子。

#2

Try

尝试

$array = preg_split('/(?: +|(=))(?=(?:[^"]*"[^"]*")*[^"]*$)/', $string, -1, PREG_SPLIT_DELIM_CAPTURE | PREG_SPLIT_NO_EMPTY);

The

该

(?=(?:[^"]*"[^"]*")*[^"]*$)

part is a lookahead assertion making sure that there is an even number of quote characters ahead in the string, therefore it will fail if the current position is between quotes:

part是一个先行断言，确保字符串前面有一个偶数个引号字符，因此如果当前位置在引号之间，它将失败：

(?=      # Assert that the following can be matched:
 (?:     # A group containing...
  [^"]*" #  any number of non-quote characters followed by one quote
  [^"]*" #  the same (to ensure an even number of quotes)
 )*      # ...repeated zero or more times,
 [^"]*   # followed by any number of non-quotes
 $       # until the end of the string
)

#3

But why bother splitting?

但为什么还要分手呢？

After a look at this old question, this simple solution comes to mind, using a preg_match_all rather than a preg_split. We can use this simple regex to specify what we want:

在看了这个老问题之后，我想到了这个简单的解决方案，使用preg_match_all而不是preg_split。我们可以使用这个简单的正则表达式来指定我们想要的东西：

"[^"]*"|\b\w+\b|=

See online demo.

见在线演示。

#1