I have a string that's like this: 1|"value"|;
我有一个像这样的字符串:1 |“value”|;
I want to split that string and have chosen |
as the separator.
我想拆分那个字符串并选择了|作为分隔符。
My code looks like this:
我的代码如下所示:
String[] separated = line.split("|");
What I get is an array that contains all characters as one entry:
我得到的是一个包含所有字符作为一个条目的数组:
separated[0] = ""
separated[1] = "1"
separated[2] = "|"
separated[3] = """
separated[4] = "v"
separated[5] = "a"
...
Does anyone know why?
Can't I split an string with |
?
有谁知道为什么?我不能用|拆分字符串吗?
11 个解决方案
#1
68
|
is treated as an OR
in RegEx. So you need to escape it:
|在RegEx中被视为OR。所以你需要逃脱它:
String[] separated = line.split("\\|");
#2
10
You have to escape the |
because it has a special meaning in a regex. Have a look at the split(..)
method.
你必须逃避|因为它在正则表达式中具有特殊含义。看看split(..)方法。
String[] sep = line.split("\\|");
The second \
is used to escape the |
and the first \
is used to escape the second \
:).
第二个\用于逃避|并且第一个\用于逃避第二个\ :)。
#3
4
The parameter to split
method is a regex, as you can read here. Since |
has a special meaning in regular expressions, you need to escape it. The code then looks like this (as others have shown already):
split方法的参数是正则表达式,您可以在这里阅读。自|在正则表达式中有特殊含义,你需要转义它。然后代码看起来像这样(正如其他人已经显示的那样):
String[] separated = line.split("\\|");
#4
3
Try this: String[] separated = line.split("\\|");
试试这个:String [] separated = line.split(“\\ |”);
My answer is better. I corrected the spelling of "separated" :)
我的回答更好。我纠正了“分开”的拼写:)
Also, the reason this works? |
means "OR" in regex. You need to escape it.
这也是有效的原因吗? |在正则表达式中表示“OR”。你需要逃脱它。
#5
3
Escape the pipe. It works.
逃离管道。有用。
String.split("\\|");
The pipe is a special character in regex meaning OR
管道是正则表达式中的特殊字符OR
#6
3
It won't work this way, because you have to escape the Pipe | first. The following sample code, found at (http://www.rgagnon.com/javadetails/java-0438.html) shows an example.
它不会以这种方式工作,因为你必须逃避Pipe |第一。以下示例代码(http://www.rgagnon.com/javadetails/java-0438.html)显示了一个示例。
public class StringSplit {
public static void main(String args[]) throws Exception{
String testString = "Real|How|To";
// bad
System.out.println(java.util.Arrays.toString(
testString.split("|")
));
// output : [, R, e, a, l, |, H, o, w, |, T, o]
// good
System.out.println(java.util.Arrays.toString(
testString.split("\\|")
));
// output : [Real, How, To]
}
}
#7
2
String.split() uses regex, so you need to escape the '|' like .split("\\|");
String.split()使用正则表达式,所以你需要转义'|'像.split(“\\ |”);
#8
2
you can replace the pipe with another character like '#' before spliting, try this
您可以在拆分之前用另一个字符替换管道,例如'#',试试这个
String[] seperated = line.replace('|','#').split("#");
#9
0
| means OR in regex, you should escape it. What's more, a single '\', you get '\|' means nothing in Java string. So you should also escape the '\' itself, which yields '\|'.
|在正则表达式中表示OR,你应该逃避它。更重要的是,单个“\”,你得到'\ |'在Java字符串中没有任何意义所以你也应该逃避'\'本身,这会产生'\ |'。
Good luck!
#10
0
public class StringUtil {
private static final String HT = "\t";
private static final String CRLF = "\r\n";
// This class cannot be instantiated
private StringUtil() {
}
/**
* Split the string into an array of strings using one of the separator in
* 'sep'.
*
* @param s
* the string to tokenize
* @param sep
* a list of separator to use
*
* @return the array of tokens (an array of size 1 with the original string
* if no separator found)
*/
public static String[] split(final String s, final String sep) {
// convert a String s to an Array, the elements
// are delimited by sep
final Vector<Integer> tokenIndex = new Vector<Integer>(10);
final int len = s.length();
int i;
// Find all characters in string matching one of the separators in 'sep'
for (i = 0; i < len; i++)
if (sep.indexOf(s.charAt(i)) != -1)
tokenIndex.addElement(new Integer(i));
final int size = tokenIndex.size();
final String[] elements = new String[size + 1];
// No separators: return the string as the first element
if (size == 0)
elements[0] = s;
else {
// Init indexes
int start = 0;
int end = (tokenIndex.elementAt(0)).intValue();
// Get the first token
elements[0] = s.substring(start, end);
// Get the mid tokens
for (i = 1; i < size; i++) {
// update indexes
start = (tokenIndex.elementAt(i - 1)).intValue() + 1;
end = (tokenIndex.elementAt(i)).intValue();
elements[i] = s.substring(start, end);
}
// Get last token
start = (tokenIndex.elementAt(i - 1)).intValue() + 1;
elements[i] = (start < s.length()) ? s.substring(start) : "";
}
return elements;
}
}
#11
0
Pattern.compile("|").splitAsStream(String you want to split).collect(Collectors.toList());
#1
68
|
is treated as an OR
in RegEx. So you need to escape it:
|在RegEx中被视为OR。所以你需要逃脱它:
String[] separated = line.split("\\|");
#2
10
You have to escape the |
because it has a special meaning in a regex. Have a look at the split(..)
method.
你必须逃避|因为它在正则表达式中具有特殊含义。看看split(..)方法。
String[] sep = line.split("\\|");
The second \
is used to escape the |
and the first \
is used to escape the second \
:).
第二个\用于逃避|并且第一个\用于逃避第二个\ :)。
#3
4
The parameter to split
method is a regex, as you can read here. Since |
has a special meaning in regular expressions, you need to escape it. The code then looks like this (as others have shown already):
split方法的参数是正则表达式,您可以在这里阅读。自|在正则表达式中有特殊含义,你需要转义它。然后代码看起来像这样(正如其他人已经显示的那样):
String[] separated = line.split("\\|");
#4
3
Try this: String[] separated = line.split("\\|");
试试这个:String [] separated = line.split(“\\ |”);
My answer is better. I corrected the spelling of "separated" :)
我的回答更好。我纠正了“分开”的拼写:)
Also, the reason this works? |
means "OR" in regex. You need to escape it.
这也是有效的原因吗? |在正则表达式中表示“OR”。你需要逃脱它。
#5
3
Escape the pipe. It works.
逃离管道。有用。
String.split("\\|");
The pipe is a special character in regex meaning OR
管道是正则表达式中的特殊字符OR
#6
3
It won't work this way, because you have to escape the Pipe | first. The following sample code, found at (http://www.rgagnon.com/javadetails/java-0438.html) shows an example.
它不会以这种方式工作,因为你必须逃避Pipe |第一。以下示例代码(http://www.rgagnon.com/javadetails/java-0438.html)显示了一个示例。
public class StringSplit {
public static void main(String args[]) throws Exception{
String testString = "Real|How|To";
// bad
System.out.println(java.util.Arrays.toString(
testString.split("|")
));
// output : [, R, e, a, l, |, H, o, w, |, T, o]
// good
System.out.println(java.util.Arrays.toString(
testString.split("\\|")
));
// output : [Real, How, To]
}
}
#7
2
String.split() uses regex, so you need to escape the '|' like .split("\\|");
String.split()使用正则表达式,所以你需要转义'|'像.split(“\\ |”);
#8
2
you can replace the pipe with another character like '#' before spliting, try this
您可以在拆分之前用另一个字符替换管道,例如'#',试试这个
String[] seperated = line.replace('|','#').split("#");
#9
0
| means OR in regex, you should escape it. What's more, a single '\', you get '\|' means nothing in Java string. So you should also escape the '\' itself, which yields '\|'.
|在正则表达式中表示OR,你应该逃避它。更重要的是,单个“\”,你得到'\ |'在Java字符串中没有任何意义所以你也应该逃避'\'本身,这会产生'\ |'。
Good luck!
#10
0
public class StringUtil {
private static final String HT = "\t";
private static final String CRLF = "\r\n";
// This class cannot be instantiated
private StringUtil() {
}
/**
* Split the string into an array of strings using one of the separator in
* 'sep'.
*
* @param s
* the string to tokenize
* @param sep
* a list of separator to use
*
* @return the array of tokens (an array of size 1 with the original string
* if no separator found)
*/
public static String[] split(final String s, final String sep) {
// convert a String s to an Array, the elements
// are delimited by sep
final Vector<Integer> tokenIndex = new Vector<Integer>(10);
final int len = s.length();
int i;
// Find all characters in string matching one of the separators in 'sep'
for (i = 0; i < len; i++)
if (sep.indexOf(s.charAt(i)) != -1)
tokenIndex.addElement(new Integer(i));
final int size = tokenIndex.size();
final String[] elements = new String[size + 1];
// No separators: return the string as the first element
if (size == 0)
elements[0] = s;
else {
// Init indexes
int start = 0;
int end = (tokenIndex.elementAt(0)).intValue();
// Get the first token
elements[0] = s.substring(start, end);
// Get the mid tokens
for (i = 1; i < size; i++) {
// update indexes
start = (tokenIndex.elementAt(i - 1)).intValue() + 1;
end = (tokenIndex.elementAt(i)).intValue();
elements[i] = s.substring(start, end);
}
// Get last token
start = (tokenIndex.elementAt(i - 1)).intValue() + 1;
elements[i] = (start < s.length()) ? s.substring(start) : "";
}
return elements;
}
}
#11
0
Pattern.compile("|").splitAsStream(String you want to split).collect(Collectors.toList());