有没有办法根据字符数（不是分隔符）将字符串拆分成多个字符串？

So if I have "7A7F6E88920AB8271A" and I want to split it into an array of strings with same amount of character count, like "7A", "7F", "6E", "88", ... is there any method ready for this, or I have to manually make it on objective C? Thanks.

所以，如果我有“7A7F6E88920AB8271A”并且我想把它拆分成具有相同字符数量的字符串数组，如“7A”，“7F”，“6E”，“88”，......是否有任何方法准备好了为此，还是我必须在目标C上手动制作它？谢谢。

1 个解决方案

#1

I am not an objective-c expert, but the following might lead you in the right direction (Regular Expressions)

我不是客观的专家，但以下内容可能会引导您朝着正确的方向前进（正则表达式）

NSRegularExpression regexp = [NSRegularExpression 
regularExpressionWithPattern:@"(\\w){2}" 
options:NSRegularExpressionCaseInsensitive error:&error];

NSArray *matches = [regex matchesInString:string options:0 
range:NSMakeRange(0, [string length])];

The RegExp (\\w){2}should find all 2-length character words and each of them are in the matches array.

RegExp（\\ w）{2}应该找到所有2个长度的字符单词，并且每个单词都在matches数组中。

Constructed from examples on this page: https://developer.apple.com/reference/foundation/nsregularexpression

根据此页面上的示例构建：https：//developer.apple.com/reference/foundation/nsregularexpression

#1