I'm passing an array via ajax to a php.
我通过ajax将数组传递给php。
$.post("send.php",{arr:arr}); //["one", "two", "three"]
How do I assign each value to an variable in php? I tried this but does not do what I need.
如何将每个值分配给php中的变量？我试过这个，但没有做我需要的。
for ($i = 0; $i < $_POST['arr']; $i++){
$var+($i+1) = $_POST['arr'][$i];
}
expected $var1 = "one", $var2 = "two",etc...
预期$ var1 =“one”，$ var2 =“two”等...
1 个解决方案
#1
5
You are trying to create a dynamic variable name. You'll have to wrap the $var with {} and concatinate with . to create dynamic variables.
您正在尝试创建动态变量名称。你必须使用{}包装$ var并使用。创建动态变量。
${"var" . ($i+1)} = $_POST['arr'][$i];
#1
5
You are trying to create a dynamic variable name. You'll have to wrap the $var with {} and concatinate with . to create dynamic variables.
您正在尝试创建动态变量名称。你必须使用{}包装$ var并使用。创建动态变量。
${"var" . ($i+1)} = $_POST['arr'][$i];