php - 在数组中查找下一行元素值

I am returning an array of values using mysql_fetch_array.

我使用mysql_fetch_array返回一个值数组。

In the while loop, i need to perform an if condition on the next element of the array.

在while循环中，我需要对数组的下一个元素执行if条件。

E.g

例如

if next($row) == 'test'
{
...
}

The thing is 'next($row)' is returning me the index of the next element in the array. I would like to test for the next $row("name").

事情是'next（$ row）'返回数组中下一个元素的索引。我想测试下一个$行（“名称”）。

if next($row("name")) == 'test'
    {
    ...
    } //this code is incorrect

Is there a way of doing this in php?

有没有办法在PHP中这样做？

Thanks a lot for your help :)

非常感谢你的帮助 ：）

2 个解决方案

#1

if the "next($row)" gives you the index of the next cell in the array then just use it to perform the test. $arr[next($row)] = the next cell value/obj/whatever you have there

如果“next（$ row）”为您提供数组中下一个单元格的索引，则只需使用它来执行测试。 $ arr [next（$ row）] =下一个单元格值/ obj /无论你有什么

#2

foreach ($rows as $k => $row) {
    if (isset($rows[$k+1]) && $rows[$k+1] == 'test') //do something

    // Do normal stuff here
}