如何检查字符串是否是几个不同的值之一？

i have a string variable which can only contain 6 different values. I want to check if it contains one of the first 4 values or one of the 2 second values.

我有一个字符串变量，只能包含6个不同的值。我想检查它是否包含前4个值之一或2个秒值之一。

Is there a more elegant way than this:

有没有比这更优雅的方式：

if string.eql? 'val1' || string.eql? 'val2' || string.eql? 'val3' || string.eql? 'val4'
  ...
elsif string.eql? 'val5' || string.eql? 'val6'
  ...
end

Maybe something like if string is in ['val1', 'val2', 'val3', 'val4']?

也许像字符串在['val1'，'val2'，'val3'，'val4']中？

3 个解决方案

#1

You could use include?:

你可以使用include？：

if ['val1', 'val2', 'val3', 'val4'].include?(string)

#2

case string
when *%w[val1 val2 val3 val4]
  ...
else
  ...
end

#3

Array#index

数组索引＃

Returns the index of the first object in ary such that the object is == to obj.Returns nil if no match is found.

返回ary中第一个对象的索引，使得对象为== to obj。如果未找到匹配则返回nil。

puts "something" if ['val1', 'val2', 'val3', 'val4'].index("val1")
# >> something

#1