I have some code that looks like this (all within the mongodb interpreter):
我有一些看起来像这样的代码(都在mongodb解释器中):
var needed_skills = ['mongodb','javascript','c++','php']
db.applicants.save( { name:'joe', skills:['c++','ruby','css'] } );
db.applicants.save( { name:'peter', skills:['mongodb','javascript','c++','php','html'] } );
How do I do a query that finds the applicant with all the required skills? Basically I'm looking for documents that have all the array members present in a given array. I know you can do something like this to find if you want it to find one member:
如何查找具有所有必需技能的申请人?基本上我正在寻找具有给定数组中所有数组成员的文档。我知道你可以做这样的事情来找到你是否想找到一个成员:
db.applicants.find({skills:'mongodb'})
However that is only matching one, where as I want to match all ...
然而,这只匹配一个,我希望匹配所有...
Any help would be greatly appreciated.
任何帮助将不胜感激。
1 个解决方案
#1
4
You want to use $all
:
你想使用$ all:
db.applicants.find({skills: {$all: ['mongodb','javascript','c++','php','html']} });
or
要么
var needed_skills = ['mongodb','javascript','c++','php']
db.applicants.find({skills: {$all: needed_skills} });
#1
4
You want to use $all
:
你想使用$ all:
db.applicants.find({skills: {$all: ['mongodb','javascript','c++','php','html']} });
or
要么
var needed_skills = ['mongodb','javascript','c++','php']
db.applicants.find({skills: {$all: needed_skills} });