mysql db结果转换为json数组

I am trying to write a auto complete, which the auto complete items load one time when the PHP page loads. With the items that are fetched from mysql DB , i have create a json array like this

我正在尝试编写一个自动完成，当PHP页面加载时，自动完成项将加载一次。使用从mysql DB获取的项，我创建了这样的json数组

<?php
$bnkArray = array();
$sql_bnk = mysql_query("SELECT BName, BCode, ID  FROM bank");
while($rBnk = mysql_fetch_array($sql_bnk)){

    $bnkDet = array(
        'label' => $rBnk['BName'],
        'value' => $rBnk['BName'],
        'otherDetails' => $rBnk['BName'].'||'. $rBnk['BCode'].'||'. $rBnk['ID'] 
    );  
    array_push($bnkArray, $bnkDet);
}

?>

i need this array as like this javascript array

我需要这个数组，就像这个javascript数组一样

<script>

var bankSource11 = [
      {
        value: "jquery",
        label: "jQuery",
        otherDetails: "the write less, do more, JavaScript library",

      },
      {
        value: "jquery-ui",
        label: "jQuery UI",
        otherDetails: "the official user interface library for jQuery",

      },
      {
        value: "sizzlejs",
        label: "Sizzle JS",
        otherDetails: "a pure-JavaScript CSS selector engine",

      }
    ];
</script>

if i call this array like this in my auto complete this is not working

如果我像这样在自动补全中调用这个数组，它就不能工作了

var bankSource = [<?php echo  $bnkArray; ?>];

what is this array type.. how to do this.

这个数组类型是什么。如何做到这一点。

this is the autocomplete part

这是自动完成的部分

$(this).autocomplete({
            minLength: 0,
            source: bankSource,
            focus: function( event, ui ) {
                $(this).val( ui.item.label );
                return false;
            },
            select: function( event, ui ) {
                console.log(ui.item.value +' ____ ' + ui.item.otherDetails);
                $( "#project" ).val( ui.item.label );
                $( "#project-id" ).val( ui.item.value );
                $( "#project-description" ).html( ui.item.otherDetails );

                return false;
              }
            })


        }

5 个解决方案

#1

Please replace

请替换

var bankSource = [<?php echo  $bnkArray; ?>];

with

与

var bankSource = <?php echo json_encode($bnkArray); ?>;

#2

Here is a sample example which i modified accroding to your requirement. Kindly study it and let me know if you have any question.

这是我根据你的要求修改的一个示例。如果您有任何问题，请仔细研究并告诉我。

 <?php
    $bnkArray = array();
    $sql_bnk = mysql_query("SELECT BName, BCode, ID  FROM bank");
    while($rBnk = mysql_fetch_array($sql_bnk)){

        $bnkDet = array(
            'label' => $rBnk['BName'],
            'value' => $rBnk['BName'],
            'otherDetails' => $rBnk['BName'].'||'. $rBnk['BCode'].'||'. $rBnk['ID'] 
        );  
        array_push($bnkArray, $bnkDet);
    }

    ?>


    <head>
      <meta charset="utf-8">
      <title>jQuery UI Autocomplete - Default functionality</title>
      <link rel="stylesheet" href="//code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css">
      <script src="//code.jquery.com/jquery-1.10.2.js"></script>
      <script src="//code.jquery.com/ui/1.11.4/jquery-ui.js"></script>
      <link rel="stylesheet" href="/resources/demos/style.css">
      <script>
      $(function() {
        var bankSource11  = <?php echo json_encode($bnkArray); ?>;
        $( "#My_Input" ).autocomplete({
          source: bankSource11  
        });
      });
      </script>
    </head>
    <body>

    <div class="ui-widget">
      <input id="My_Input">
    </div>

#3

change this line like this,

像这样改变这条线，

var bankSource = [<?php echo  $bnkArray; ?>];

来

var bankSource = "<?php echo  json_encode($bnkArray); ?>";

Php variable is enclosed with quotes and assigned to js variable.

Php变量用引号括起来，并赋给js变量。

#4

You should do following :

你应该做以下事情:

var bankSource11 = [<?php echo json_encode($bnkArray); ?>];

#5

Note the single quotes, because it's string:

注意单引号，因为它是字符串:

var bankSource = '<?php echo json_encode($bnkArray); ?>';

#1