oracle 日期格式化和数据去重

时间：2024-03-06 22:45:22

1、获取系统日期：

select sysdate as date1 from dual；
   
当前时间减去7分钟的时间   
select sysdate,sysdate - interval \'7\' MINUTE FROM dual;  
当前时间减去7小时的时间   
select sysdate,sysdate - interval \'7\' HOUR FROM dual;   
当前时间减去7天的时间   
select sysdate,sysdate - interval \'7\' DAY FROM dual;   
（select (sysdate-7) as date1 from dual）
当前时间减去7月的时间   
select sysdate,sysdate - interval \'7\' MONTH FROM dual;   
当前时间减去7年的时间   
select sysdate,sysdate - interval \'7\' YEAR FROM dual;   
时间间隔乘以一个数字   
select sysdate,sysdate - 8*interval \'2\' HOUR FROM dual;

 

2、日期转换方法：

to_date( \'2020-01-01 13:14:20 \', \'yyyy-mm-dd hh24:mi:ss\')

3、根据某个字段去重：

--I、Name相同ID最小的记录(推荐用1,2,3),方法3在SQl05时，效率高于1、2
方法1:
Select * from #T a where not exists(select 1 from #T where Name=a.Name and ID<a.ID)
 
方法2:
select a.* from #T a join (select min(ID)ID,Name from #T group by Name) b on a.Name=b.Name and a.ID=b.ID
 
方法3:
select * from #T a where ID=(select min(ID) from #T where Name=a.Name)
 
方法4:
select a.* from #T a join #T b on a.Name=b.Name and a.ID>=b.ID group by a.ID,a.Name,a.Memo having count(1)=1 
 
方法5:
select * from #T a group by ID,Name,Memo having ID=(select min(ID)from #T where Name=a.Name)
 
方法6:
select * from #T a where (select count(1) from #T where Name=a.Name and ID<a.ID)=0
 
方法7:
select * from #T a where ID=(select top 1 ID from #T where Name=a.name order by ID)
 
方法8:
select * from #T a where ID!>all(select ID from #T where Name=a.Name)
 
方法9(注:ID为唯一时可用):
select * from #T a where ID in(select min(ID) from #T group by Name)
 
--SQL2005:
 
方法10:
select ID,Name,Memo from (select *,min(ID)over(partition by Name) as MinID from #T a)T where ID=MinID
 
方法11:
 
select ID,Name,Memo from (select *,row_number()over(partition by Name order by ID) as MinID from #T a)T where MinID=1

 

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