设计一个10*10的棋盘:
行号、列号单独输出
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package yu;
import java.util.Scanner;
public class WuZiQi {
/*● 棋子1
○ 棋子2
*
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
String [] [] qipan= new String [ 10 ] [ 10 ];
//初始化棋盘:
for ( int k= 0 ;k<qipan.length;k++){
for ( int q= 0 ;q<qipan[k].length;q++){
qipan[k][q]= "+ " ;
}
}
//输出棋盘:
System.out.print( " " );
for ( int i= 0 ;i< 10 ;i++){
System.out.print(i+ " " );
}
System.out.println();
for ( int k= 0 ;k<qipan.length;k++){
System.out.print(k+ " " );
for ( int q= 0 ;q<qipan[k].length;q++){
System.out.print(qipan[k][q]);
}
System.out.println();
}
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输入坐标下棋(x,y),并作容错处理:
- 保证输入的坐标是(x,y);
- 下标越界处理;
- 判断此坐标有无棋子;
- 确保坐标输入为数字。
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int x,y; //储存下棋坐标:
Scanner sc= new Scanner(System.in);
boolean flag= true ; //区分黑白棋;
while ( true ){
System.out.println( "请输入坐标下棋,坐标格式(x,y)" );
String str=sc.nextLine();
String [] str1=str.split( "," );
//容错处理1
if (str1.length!= 2 ){
System.out.println( "坐标输入错误,请重新输入!!" );
} else {
//容错处理3
try {
x=Integer.parseInt(str1[ 0 ]);
y=Integer.parseInt(str1[ 1 ]);
} catch (Exception e){
System.out.println( "坐标输入错误,请重新输入!!" );
continue ;
}
//容错处理2--下标越界
if (x>= 10 ||y>= 10 ){
System.out.println( "坐标输入错误,请重新输入!!" );
} else {
//容错处理--判断当前位置是否有棋子:
//黑白棋:
if (qipan[x][y].equals( "+ " )){
if (flag){
qipan[x][y]= "● " ;
} else {
qipan[x][y]= "○ " ;
}
flag=!flag;
} else {
System.out.println( "当前位置已有棋子,请重新输入坐标!!" );
continue ;
}
//输出棋盘:
System.out.print( " " );
for ( int i= 0 ;i< 10 ;i++){
System.out.print(i+ " " );
}
System.out.println();
for ( int k= 0 ;k<qipan.length;k++){
System.out.print(k+ " " );
for ( int q= 0 ;q<qipan[k].length;q++){
System.out.print(qipan[k][q]);
}
System.out.println();
}
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判断是否五子连珠:
8个方向,4条线
- 上方&下方
- 左方&右方
- 左斜上&右斜下
- 右斜上&左斜下
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//判断是否五子连珠:
int count= 1 ;
String currentZiQi=qipan[x][y]; //储存当前下的棋子;
//判断上方:
for ( int k=x- 1 ;k>= 0 ;k--){
if (qipan[k][y].equals(currentZiQi)){
count++;
} else {
break ;
}
}
if (count>= 5 ){
System.out.println(currentZiQi+ "获胜!!!" );
break ;
}
//判断下方:
for ( int k=x+ 1 ;k< 10 ;k++){
if (qipan[k][y].equals(currentZiQi)){
count++;
} else {
break ;
}
}
if (count>= 5 ){
System.out.println(currentZiQi+ "获胜!!!" );
break ;
}
count= 1 ; //重置count;
//判断左边:
for ( int k=y- 1 ;k>= 0 ;k--){
if (qipan[x][k].equals(currentZiQi)){
count++;
} else {
break ;
}
}
if (count>= 5 ){
System.out.println(currentZiQi+ "获胜!!!" );
break ;
}
//判断右边:
for ( int k=y+ 1 ;k< 10 ;k++){
if (qipan[x][k].equals(currentZiQi)){
count++;
} else {
break ;
}
}
if (count>= 5 ){
System.out.println(currentZiQi+ "获胜!!!" );
break ;
}
count= 1 ;
//判断左上斜边:
for ( int k=x- 1 ,j=y- 1 ;k>= 0 &&j>= 0 ;k--,j--){
if (qipan[k][j].equals(currentZiQi)){
count++;
} else {
break ;
}
}
if (count>= 5 ){
System.out.println(currentZiQi+ "获胜!!!" );
break ;
}
//右下斜方:
for ( int k=x+ 1 ,j=y+ 1 ;k< 10 &&j< 10 ;k++,j++){
if (qipan[k][j].equals(currentZiQi)){
count++;
} else {
break ;
}
}
if (count>= 5 ){
System.out.println(currentZiQi+ "获胜!!!" );
break ;
}
count= 1 ;
//左下斜方:
for ( int k=x- 1 ,j=y+ 1 ;k>= 0 &&j< 10 ;k--,j++){
if (qipan[k][j].equals(currentZiQi)){
count++;
} else {
break ;
}
}
if (count>= 5 ){
System.out.println(currentZiQi+ "获胜!!!" );
break ;
}
//右上斜方:
for ( int k=x+ 1 ,j=y- 1 ;k< 10 &&j>= 0 ;k++,j--){
if (qipan[k][j].equals(currentZiQi)){
count++;
} else {
break ;
}
}
if (count>= 5 ){
System.out.println(currentZiQi+ "获胜!!!" );
break ;
}
count= 1 ;
}
}
}
}
}
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总结
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原文链接:https://blog.csdn.net/m0_53246877/article/details/113333770