Python自然排序元组列表(纸牌游戏)

I am developing a text based game of Go Fish as a way of practicing/learning python. I want to sort the cards in the players hand for readability and am running into issues.

我正在开发一种基于文本的Go Fish游戏，作为练习/学习python的一种方式。我想把玩家手中的牌进行分类，以提高可读性，同时也会遇到一些问题。

my_hand = [('3', 'Spades'), ('Ace', 'Hearts'), ('10', 'Clubs'), ('King', 'Diamonds'), ('4', 'Clubs')]

if I do:

如果我做的事:

my_hand.sort()

I get:

我得到:

[('10', 'Clubs'), ('3', 'Spades'), ('4', 'Clubs'), ('Ace', 'Hearts'), ('King', 'Diamonds')]

I don't want the 10 to come first. But because I have 'Ace', 'King' 'Queen' 'Jack' as card values I can't sort as an int.

我不想让这10个人先来。但因为我有“Ace”，“King”“Queen”“Jack”作为card值，我不能将其排序为int。

this is what I came up with. But I'm thinking there has to be a better way to do it, and the goal of this project is to learn new methods so I thouhgt I'd ask.

这就是我想到的。但是我认为必须有更好的方法来完成它，这个项目的目标是学习新的方法，所以我想我会问。

my solution:

我的解决方案:

def natural_sort(hand):
    number_cards = []
    ten_cards = []
    face_cards = []
    new_hand = []
    for card in hand:
        try:
            int(card[0])
            if card[0] != 10:
                number_cards.append(card)
            elif card[0] == 10:
                ten_cards.append(card)
        except ValueError:
            face_cards.append(card)
    number_cards.sort()
    face_cards.sort()
    new_hand.extend(number_cards)
    new_hand.extend(ten_cards)
    new_hand.extend(face_cards)
    return new_hand

Thoughts?

想法吗?

2 个解决方案

#1

What you can do is assign a number value to your cards, as there are only 4 face cards. For example, say Ace=1, Jack=11, and so on.

你能做的是给你的卡片分配一个数字值，因为只有4张脸卡。例如，Ace=1, Jack=11，等等。

#2

This is a nice use-case for a custom comparator! A comparator is a function used by a sorting algorithm to compare two items. cmp(a, b) returns -1 if a < b, 0 if a == b, and 1 if a > b.

对于自定义比较器来说，这是一个很好的用例!比较器是排序算法用来比较两个项目的函数。cmp(a, b)返回-1，如果a < b，则为0，如果a == b，如果> b为1。

To get the sort you want, you could do:

为了得到你想要的那种，你可以:

hand = [('10', 'Clubs'), ('3', 'Spades'), ('4', 'Clubs'), ('Ace', 'Hearts'), ('King', 'Diamonds')]

def card_cmp(card1, card2):
    try:
        c1num = int(card1[0])
    except ValueError:
        c1num = False

    try:
        c2num = int(card2[0])
    except ValueError:
        c2num = False

    if c1num and c2num:
        return cmp(c1num, c2num)
    elif c1num:
        return -1
    elif c2num:
        return 1
    else:
        return cmp(card1[0], card2[0])

print sorted(hand, cmp=card_cmp)

If you also want to sort the face cards by value rather than alphabetically, you'd have to encode that order somewhere, maybe with a dictionary like

如果您还想按值而不是按字母顺序对面孔卡片进行排序，那么您需要在某个地方编码该顺序，可能需要使用字典。

face_cards = { 
  'Jack' : 11,
  'Queen' : 12,
  'King' : 13,
  'Ace' : 14,
}

and then your comparator could just be

然后你的比较器就可以了。

def card_cmp(card1, card2):
    try:
        c1num = int(card1[0])
    except ValueError:
        c1num = face_cards[card1[0]]

    try:
        c2num = int(card2[0])
    except ValueError:
        c2num = face_cards[card2[0]]

    return cmp(c1num, c2num)

#1