Python实作练习100题（部分）

时间：2021-01-26 01:22:18

记录一下这些练习的个人实作。

1.题目：有四个数字：1、2、3、4，能组成多少个互不相同且无重复数字的三位数？各是多少？

list = []
list_num = [1,2,3,4]


for i in list_num: 
	for j in list_num: 
		for k in list_num: 
			if (j != i and k != j and k != i):
				a  = i*100 + j*10 + k 
				list.append(a)
								
print (list)

print ("排列列表：")
col_num = 0
#for i in range(len(list)):
for i in list: 	
	col_num = col_num + 1
	#print('%-5d' %(list[i]),end="")
	print('%-5d' %i,end="")
	if col_num > 3 :
		col_num = 0	
		print ("")

2.题目：企业发放的奖金根据利润提成。利润(I)低于或等于10万元时，奖金可提10%；利润高于10万元，低于20万元时，低于10万元的部分按10%提成，高于10万元的部分，可提成7.5%；20万到40万之间时，高于20万元的部分，可提成5%；40万到60万之间时高于40万元的部分，可提成3%；60万到100万之间时，高于60万元的部分，可提成1.5%，高于100万元时，超过100万元的部分按1%提成，从键盘输入当月利润I，求应发放奖金总数？

tc_dic = {0:0.1, 10:0.075, 20:0.05, 40:0.03, 60: 0.015, 100:0.01}

def cal_bonus(num,dic):
	bonus = 0
	gear = list(dic.keys())
	rate = list(dic.values())
	cal_num = num
	
	i = 0		
	#while i < len(gear):	
	while i in range(len(gear)):	
		#print("i=%d gear=[%d ~ %d]" %(i,gear[i],gear[i+1]))
		#print("cal_num=%d" %cal_num)
		if cal_num <= gear[i+1]: 	
			bonus += cal_num*10000*(rate[i])
			#print("i=%d bonus=%d" %(i,bonus))
			#print("over");
			break
		else:
			bonus += gear[i+1]*10000*(rate[i])
			cal_num -= gear[i+1]
		i += 1	
		#print("i=%d bonus=%d" %(i,bonus))	
	print("总奖金：")
	print(bonus)

prof = input("请输入利润：")

cal_bonus(int(prof),tc_dic)

3.题目：输入某年某月某日，判断这一天是这一年的第几天？

day_cnts = [31,28,31,30,31,30,31,31,30,31,30,31]

year = input("请输入年：")
year_num = int(year)
leap = 0
if (year_num % 400 == 0) or ((year_num % 4 == 0) and (year_num % 100 != 0)):
    leap = 1   
month = input("请输入月：")
month_num = int(month)
if month_num not in range(1,13):
	print("错误的月份:%d月" %month_num)  
	exit()
day = input("请输入日：")
day_num = int(day)
if month_num == 2:
	if day_num not in range(1,28+leap+1):
		 print("该年2月错误的天数：%d天" %day_num) 
		 exit()
else:
	if day_num not in range(1,day_cnts[month_num]):
		print("错误的天数：%d天" %day_num) 	
		exit()
		
day_in_year = 0

i = 0    
while i < (month_num-1):
	day_in_year += day_cnts[i]
	if i == 2:
		day_in_year += leap
	i += 1	
day_in_year += day_num 	
print("%4d/%2d/%2d是%4d年的第%d天" %(year_num,month_num,day_num,year_num,day_in_year))

4.题目：斐波那契数列。

l = []	
	
def fib(n):
	a,b = 1,1
	for i in range(n-1):
		a,b = b,a+b
		l.append(a)    
	#return a	

fib(10)

print(l)

5.题目：输出 9*9 乘法口诀表。

for i in range(1,10):
	if i > 1:
		print("")
	for j in range(1,i+1):
		print("%d*%d=%d   " %(i,j,i*j),end="")
print("")

6.题目：文本颜色设置

class bcolors:
	HEADER = '\033[95m'
	OKBLUE = '\033[94m'
	OKGREEN = '\033[92m'
	WARNING = '\033[93m'
	FAIL = '\033[91m'
	ENDC = '\033[0m'
	BOLD = '\033[1m'
	UNDERLINE = '\033[4m'
print(bcolors.WARNING + "警告的颜色字体?" + bcolors.ENDC)

7.题目：使用lambda来创建匿名函数。这题示例有点意思，解读一下。

MAXIMUM = lambda x,y :  (x > y) * x + (x < y) * y
MINIMUM = lambda x,y :  (x > y) * y + (x < y) * x
 
if __name__ == '__main__':
	a = 10
	b = 20
	print ('The largar one is %d' % MAXIMUM(a,b))
	print ('The lower one is %d' % MINIMUM(a,b))

(x > y) * x + (x < y) * y

如 x > y成立，则 x > y == true == 1，反之此时 x < y == false == 0；

(x > y) * y + (x < y) * x这句也是一样的原理。

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