1例如:要把如图1的字段拆分图2
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select account_id,
substring_index(substring_index(a.related_shop_ids, ','
,b.help_topic_id+1), ',' ,-1) shopid
from
sales_hang_account a
join
mysql.help_topic b
on b.help_topic_id < (length(a.related_shop_ids) - length( replace (a.related_shop_ids, ',' , '' ))+1)
order by a.account_id
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2:然后和shops表进行连接查询取出我们需要的字段,我这里需要取出name
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select s.` name ` as shopname,a.account_id from shops s
inner join (
select account_id,
substring_index(substring_index(a.related_shop_ids, ','
,b.help_topic_id+1), ',' ,-1) shopid
from
sales_hang_account a
join
mysql.help_topic b
on b.help_topic_id < (length(a.related_shop_ids) - length( replace (a.related_shop_ids, ',' , '' ))+1)
order by a.account_id)a on s.shop_id=a.shopid
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3:将 account_id相同合并成一行,以逗号隔开
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//这两个是网上的例子
select id,group_concat( name ) as name from table group by id;
select id,group_concat( name separator ';' ) as name from a group by id;
//借助上面两个参考
select account_id,group_concat(shopname separator ',' ) as shopname from ( select s.` name ` as shopname,a.account_id from shops s
inner join (
select account_id,
substring_index(substring_index(a.related_shop_ids, ','
,b.help_topic_id+1), ',' ,-1) shopid
from
sales_hang_account a
join
mysql.help_topic b
on b.help_topic_id < (length(a.related_shop_ids) - length( replace (a.related_shop_ids, ',' , '' ))+1)
order by a.account_id)a on s.shop_id=a.shopid) a group by account_id
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效果如下
第二种方法
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select g.account_id,g.related_shop_ids,group_concat(s. name ) as shopname from sales_hang_account g left join shops s on find_in_set(s.shop_id , g.related_shop_ids)
group by g.account_id
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sqlserver
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[product] -- 该字段存储格式为 7,8,9,11,10,12 ,数据类型为nvarchar
select id,productname=stuff(( select ',' + product_chinaname from base_supplier_product where charindex( ',' +ltrim(productid)+ ',' , ',' + product + ',' ) > 0 for xml path( '' ) ), 1, 1, '' )
from base_pre_sale_project
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结果
到此这篇关于mysql将一个字段中以逗号分隔的取出来形成新的字段实现的文章就介绍到这了,更多相关mysql字段逗号分隔内容请搜索服务器之家以前的文章或继续浏览下面的相关文章希望大家以后多多支持服务器之家!
原文链接:https://www.cnblogs.com/weixin18/p/9827222.html