将字符串作为函数参数传递

I would like to use a string as argument of a function in order to use this string for the plotting of the result, but R plots the argument variable name instead of its string value. I tried different solutions (diparse, as.character...) but still no solution. Do you have any idea?

我想使用字符串作为函数的参数,以便使用此字符串来绘制结果,但R绘制参数变量名称而不是其字符串值。我尝试了不同的解决方案(diparse,as.character ......)但仍然没有解决方案。你有什么主意吗?

mcnemar_test <- function (c1,c2,class1, class2)
{
    name1=label(class1)
    name2=deparse(substitute(class2))

    v1 = c1$encerts
    v2 = c2$encerts

    e00 = sum(ifelse(v1+v2==0,1,0)) #bad classification for both
    e01 = sum(ifelse(v1<v2,1,0)) #bad classification for 1
    e10 = sum(ifelse(v1>v2,1,0)) #bad classification for 2
    e11 = sum(ifelse(v1+v2==2,1,0)) #good classification for both

    matriu <- matrix(c(e00,e01,e10,e11),nrow = 2, 
        dimnames = list(name1 = c("Disapprove", "Approve"),
                       name2 = c("Disapprove", "Approve")))
    print (matriu)
    t <- mcnemar.test(matriu)
    return (t)
}
mcnemar_test(classifiers.NaiveBayes,classifiers.CART,"aa","bb")

I would like to see "aa" and "bb" but see "name1 and name2

我想看“aa”和“bb”但是看“name1和name2

2 个解决方案

#1

R thinks you want the names to be "name1" and "name2", just like if I were to create a list with names "a" and "b":

R认为你想要名字是“name1”和“name2”,就像我要创建一个名为“a”和“b”的列表一样:

my.list <- list(a=1, b=2)

Try using structure and passing the names as a character vector:

尝试使用结构并将名称作为字符向量传递:

matriu <- matrix(c(e00,e01,e10,e11),nrow = 2, 
                 dimnames = structure(list(c("Disapprove", "Approve"),
                                           c("Disapprove", "Approve")),
                                      names=c(class1, class2)))

Or setting the names of the elements after you create the list:

或者在创建列表后设置元素的名称:

matriu <- matrix(c(e00,e01,e10,e11),nrow = 2, 
                 dimnames = list(c("Disapprove", "Approve"),
                                 c("Disapprove", "Approve")))
names(dimnames(matriu)) <- c(class1, class2)

#2

-1

Edit: Within your function code drop the label(.) and deparse(substitute(.)) attempts and use this:

编辑:在你的功能代码中删除标签(。)和deparse(替换(。))尝试并使用它:

dimnames = setNames( list(  c("Disapprove", "Approve"),  
                            c("Disapprove", "Approve")), 
                     c(class1, class2) )

#1