/************************************************************************/
/* 题目描述：
This time, you are supposed to find A+B where A and B are two matrices, and then count the number of zero rows and columns.
输入：
The input consists of several test cases, each starts with a pair of positive integers M and N (≤10) which are the number of rows and columns of the matrices, respectively. Then 2*M lines follow, each contains N integers in [-100, 100], separated by a space. The first M lines correspond to the elements of A and the second M lines to that of B.
The input is terminated by a zero M and that case must NOT be processed.
输出：
For each test case you should output in one line the total number of zero rows and columns of A+B.
样例输入：
2 2
1 1
1 1
-1 -1
10 9
2 3
1 2 3
4 5 6
-1 -2 -3
-4 -5 -6
0
样例输出：
1
5 */
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#include <iostream>
using namespace std;
//#define MAXCOL 10
//#define MAXINT 100
//#define MININT -100 int main()
{
short arr[][];
short m, n;
while((cin>>m),m)
{
cin>>n;
short i,j,temp,count;
for(i=;i<m;i++)
for(j=;j<n;j++)
cin>>arr[i][j];
for(i=;i<m;i++)
for(j=;j<n;j++)
{
cin>>temp;
arr[i][j]+=temp;
}
i = j = temp = count = ;
for(i=; i<m; i++)
{
temp = ;
for(j=; j<n; j++)
temp += arr[i][j];
if(!temp)count++;
}
for(j=; j<n; j++)
{
temp = ;
for(i=; i<m; i++)
temp += arr[i][j];
if(!temp)count++;
}
cout<<count<<endl;
}
}