Here is my code:
这是我的代码:
from main import settings
import dropbox
def create(request):
if request.method == "POST":
image = request.FILES['image']
dbx = dropbox.Dropbox(settings.DROPBOX_ACCESS_TOKEN)
imageName = "{}.{}".format(uuid.uuid4(), image._name.split('.')[-1])
path = settings.DROPBOX_FOLDER + imageName
response = dbx.files_upload(image, path)
How can I take url of image in a variable 'image_url'? Sorry for my English.
如何在变量'image_url'中获取图像的网址?对不起我的英语不好。
1 个解决方案
#1
1
It sounds like you're looking for the sharing_create_shared_link method in the Dropbox Python SDK.
听起来你正在寻找Dropbox Python SDK中的sharing_create_shared_link方法。
The basic idea would likely be something like:
基本想法可能是这样的:
dbx.sharing_create_shared_link(path)
#1
1
It sounds like you're looking for the sharing_create_shared_link method in the Dropbox Python SDK.
听起来你正在寻找Dropbox Python SDK中的sharing_create_shared_link方法。
The basic idea would likely be something like:
基本想法可能是这样的:
dbx.sharing_create_shared_link(path)