前些天有位网友建议我在博客中添加RSS订阅功能，觉得挺好，所以自己抽空看了一下如何在Django中添加RSS功能，发现使用Django中的syndication feed framework很容易实现。
具体实现步骤和代码如下：
1、Feed类
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# -*- coding: utf-8 -*-
from django.conf import settings
from django.contrib.syndication.views import Feed
from django.utils.feedgenerator import Rss201rev2Feed
from blog.models import Article
from .constants import SYNC_STATUS
class ExtendedRSSFeed(Rss201rev2Feed):
mime_type = 'application/xml'
"""
Create a type of RSS feed that has content:encoded elements.
"""
def root_attributes(self):
attrs = super(ExtendedRSSFeed, self).root_attributes()
attrs['xmlns:content'] = 'http://purl.org/rss/1.0/modules/content/'
return attrs
def add_item_elements(self, handler, item):
super(ExtendedRSSFeed, self).add_item_elements(handler, item)
handler.addQuickElement(u'content:encoded', item['content_encoded'])
class LatestArticleFeed(Feed):
feed_type = ExtendedRSSFeed
title = settings.WEBSITE_NAME
link = settings.WEBSITE_URL
author = settings.WEBSITE_NAME
description = settings.WEBSITE_DESC + u"关注python、django、vim、linux、web开发和互联网"
def items(self):
return Article.objects.filter(hided=False, published=True, sync_status=SYNC_STATUS.SYNCED).order_by('-publish_date')[:10]
def item_extra_kwargs(self, item):
return {'content_encoded': self.item_content_encoded(item)}
def item_title(self, item):
return item.title
# item_link is only needed if NewsItem has no get_absolute_url method.
def item_link(self, item):
return '/article/%s/' % item.slug
def item_description(self, item):
return item.description
def item_author_name(self, item):
return item.creator.get_full_name()
def item_pubdate(self, item):
return item.publish_date
def item_content_encoded(self, item):
return item.content
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2、URL配置
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from django import VERSION
if VERSION[0: 2] > (1, 3):
from django.conf.urls import patterns, include, url
else:
from django.conf.urls.defaults import patterns, include, url
from .feeds import LatestArticleFeed
urlpatterns = patterns(
'',
url(r'^feed/$', LatestArticleFeed()),
)
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