Amazon "s3cmd ls" takes like this output:
Amazon“s3cmd ls”的输出如下:
2010-02-20 21:01 1458414588 s3://file1.tgz.00<br>
2010-02-20 21:10 1458414527 s3://file1.tgz.01<br>
2010-02-20 22:01 1458414588 s3://file2.tgz.00<br>
2010-02-20 23:10 1458414527 s3://file2.tgz.01<br>
2010-02-20 23:20 1458414588 s3://file2.tgz.02<br>
<br>
How to select all files of archive, ending at 00 ... XX, with the latest date of fileset ?
如何选择所有存档文件，以00结束…XX，文件集的最新日期?
Date and time is not sorted.
日期和时间没有排序。
Bash, regexp ?
Bash,正则表达式?
Thanx!
谢谢!
3 个解决方案
#1
9
DATE=$(s3cmd ls | sort -n | tail -n 1 | awk '{print $1}')
s3cmd ls | grep $DATE
sorting as a number schould put youngest dates last. Tail -n1 takes the last line, awk cuts the first word which is the date. Use that to get all entries of that date.
把最年轻的日期排在最后。尾部-n1取最后一行，awk切掉第一个词，也就是日期。使用它获取该日期的所有条目。
But maybe I didn't understand the question - so you have to rephrase it. You tell us 'date and time is not sorted' and provide an example where they are sorted - you ask for the latest date, but all entries have the same date.
但也许我不理解这个问题，所以你必须重新措辞。您告诉我们“日期和时间没有排序”，并提供它们排序的示例——您询问最近的日期，但所有条目的日期都是相同的。
#2
9
s3cmd ls s3://bucket/path/ | sort -k1,2
This will sort by date ascending.
这将按日期升序排序。
#3
0
Try
试一试
This command syntax is s3 ls s3:// path of the bucket / files | sort
这个命令语法是s3 ls s3:// bucket / file |排序的路径
s3cmd ls s3://file1.tgz.00<br> | sort
It will sort in the descending date at last
它最终将按降序排序
#1
9
DATE=$(s3cmd ls | sort -n | tail -n 1 | awk '{print $1}')
s3cmd ls | grep $DATE
sorting as a number schould put youngest dates last. Tail -n1 takes the last line, awk cuts the first word which is the date. Use that to get all entries of that date.
把最年轻的日期排在最后。尾部-n1取最后一行，awk切掉第一个词，也就是日期。使用它获取该日期的所有条目。
But maybe I didn't understand the question - so you have to rephrase it. You tell us 'date and time is not sorted' and provide an example where they are sorted - you ask for the latest date, but all entries have the same date.
但也许我不理解这个问题，所以你必须重新措辞。您告诉我们“日期和时间没有排序”，并提供它们排序的示例——您询问最近的日期，但所有条目的日期都是相同的。
#2
9
s3cmd ls s3://bucket/path/ | sort -k1,2
This will sort by date ascending.
这将按日期升序排序。
#3
0
Try
试一试
This command syntax is s3 ls s3:// path of the bucket / files | sort
这个命令语法是s3 ls s3:// bucket / file |排序的路径
s3cmd ls s3://file1.tgz.00<br> | sort
It will sort in the descending date at last
它最终将按降序排序