一、Description
Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address
is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the
first 8 positions of the binary systems are:
is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the
first 8 positions of the binary systems are:
27 26 25 24 23 22 21 20 128 64 32 16 8 4 2 1
Input
The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.
Output
The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.
二、题解
今天见鬼了，碰到这么多水题。这题就是在采用什么读取输入流时纠结了一下，最后还是用了SC,然后再用字符串的性质解决了问题。
三、java代码
二、题解
今天见鬼了，碰到这么多水题。这题就是在采用什么读取输入流时纠结了一下，最后还是用了SC,然后再用字符串的性质解决了问题。
三、java代码
import java.util.Scanner;
public class Main {
public static int transform(String s){
int sum=0;
if(s.charAt(0)=='1')
sum+=128;
if(s.charAt(1)=='1')
sum+=64;
if(s.charAt(2)=='1')
sum+=32;
if(s.charAt(3)=='1')
sum+=16;
if(s.charAt(4)=='1')
sum+=8;
if(s.charAt(5)=='1')
sum+=4;
if(s.charAt(6)=='1')
sum+=2;
if(s.charAt(7)=='1')
sum+=1;
return sum;
}
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n,i;
String s;
n=sc.nextInt();
for(i=0;i<n;i++){
s=sc.next();
System.out.println(transform(s.substring(0,8))+"."+transform(s.substring(8,16))+"."
+transform(s.substring(16,24))+"."+transform(s.substring(24,32)));
}
}
}