I need to be able to determine if a part of an image (outside of predetermined crop marks) contains any image content.
我需要能够确定图像的一部分(在预定裁剪标记之外)是否包含任何图像内容。
Is there a way with ImageMagick (specifically the php interface) to do this?
有没有办法使用ImageMagick(特别是php界面)来做到这一点?
Scenario: The canvas is 8.5x11 with .5 in margins on the top, left, and bottom edges and a 1 in margin on the right edge. The image needs to fit within the crop marks for printing.
场景:画布为8.5x11,顶部,左侧和底部边缘的边距为0.5,右边缘的边距为1。图像需要适合裁剪标记以进行打印。
Normally I use Photoshop actions to do this, but I am trying to automate the process.
通常我使用Photoshop操作来执行此操作,但我正在尝试自动执行此过程。
1 个解决方案
#1
2
Replace everything within crop marks with black/white rectangle, do a histogram of the resulting image and analyze it?
用黑/白矩形替换裁剪标记内的所有内容,对结果图像进行直方图分析并进行分析?
I can do this with command-line version of ImageMagick, but dont know how to express it with PHP api.
我可以使用命令行版本的ImageMagick来做到这一点,但不知道如何使用PHP api表达它。
#1
2
Replace everything within crop marks with black/white rectangle, do a histogram of the resulting image and analyze it?
用黑/白矩形替换裁剪标记内的所有内容,对结果图像进行直方图分析并进行分析?
I can do this with command-line version of ImageMagick, but dont know how to express it with PHP api.
我可以使用命令行版本的ImageMagick来做到这一点,但不知道如何使用PHP api表达它。