如何从此数组到新数组的特定键值对？

array

[{
    "key":"Passed",
    "values":[[date1,time1],[date2,time2]]
},{
    "key":"Failed",
    "values":[[date3,time3],[date4,time4]]
}]

Say i want to copy key:failed and values [date3,time3] to a new array, how do i do it?

假设我想复制密钥:失败并将值[date3,time3]复制到一个新数组,我该怎么办?

2 个解决方案

#1

First you will want to identify the object in the array by it's key. Lets assume you array is stored in a variable called mylist

首先,您需要通过它的键来识别数组中的对象。让我们假设您的数组存储在一个名为mylist的变量中

var error = mylist.find(function(item){ return item.key === 'Failed'; });

now assuming you have a new array:

现在假设你有一个新的数组:

var failed = []; // your new array
failed.push({
    key: error.key,
    values: error.values[0] // assuming you only want the first value
});

There may be a better application for this though. If you could provide more context around what you want achieve.

尽管如此,可能有更好的应用。如果您可以提供更多关于您想要实现的内容。

EDIT:

If you are looking to grab every failed result from the array and group them into a subset you may want user the reduce method to do the following.

如果您希望从阵列中获取每个失败的结果并将它们分组到子集中,您可能希望用户使用reduce方法执行以下操作。

var failed = mylist.reduce(function(mem, item) {
    if(item.key === 'Failed'){
        var transformed = {
            key: error.key,
            values: error.values[0]
        };
        mem.push(transform)
    }
    return mem;
}, []);

#2

Using just JavaScript

仅使用JavaScript

var newArray = [];

for(var i=0; i<=array.length; i++){
 if (array[i]['key'] === "Failed"){
    newArray.push(array[i]);
  }
}

newArray contains all the failed items.

newArray包含所有失败的项目。

#1