python实现判断一个字符串是否是合法IP地址的示例

时间:2022-04-17 16:49:35

一个刚结束的笔试题目,简单贴一下吧,下面是具体实现:

?
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
#!usr/bin/env python
#encoding:utf-8
'''
__Author__:沂水寒城
功能:判断一个字符串是否是合法IP地址
'''
import re
def judge_legal_ip(one_str):
 '''
 正则匹配方法
 判断一个字符串是否是合法IP地址
 '''
 compile_ip=re.compile('^((25[0-5]|2[0-4]\d|[01]?\d\d?)\.){3}(25[0-5]|2[0-4]\d|[01]?\d\d?)$')
 if compile_ip.match(one_str):
  return True
 else:
  return False
def judge_legal_ip2(one_str):
 '''
 简单的字符串判断
 '''
 if '.' not in one_str:
  return False
 elif one_str.count('.')!=3:
  return False
 else:
  flag=True
  one_list=one_str.split('.')
  for one in one_list:
   try:
    one_num=int(one)
    if one_num>=0 and one_num<=255:
     pass
    else:
     flag=False
   except:
    flag=False
  return flag
     
if __name__=='__main__':
 ip_list=['','172.31.137.251','100.10.0.1000','1.1.1.1','12.23.13','aa.12.1.2','12345678','289043jdhjkbh']
 for one_str in ip_list:
  if judge_legal_ip(one_str): #正则方法
  #if judge_legal_ip2(one_str): #字符串方法
   print '{0} is a legal ip address!'.format(one_str)
  else:
   print '{0} is not a legal ip address!'.format(one_str)

结果如下:

?
1
2
3
4
5
6
7
8
is not a legal ip address!
172.31.137.251 is a legal ip address!
100.10.0.1000 is not a legal ip address!
1.1.1.1 is a legal ip address!
12.23.13 is not a legal ip address!
aa.12.1.2 is not a legal ip address!
12345678 is not a legal ip address!
289043jdhjkbh is not a legal ip address!

以上这篇python实现判断一个字符串是否是合法IP地址的示例就是小编分享给大家的全部内容了,希望能给大家一个参考,也希望大家多多支持服务器之家。

原文链接:https://blog.csdn.net/together_cz/article/details/77533082