I want to use a URL like this:
我想使用这样的URL:
site.com/car-list/param1/value1/param2/value2
"car" is variable and can be anytihng. i solved the "site.com/car-list" part like this:
“汽车”是可变的,可以是任何人。我解决了“site.com/car-list”这样的部分:
$categoryRoute = new Zend_Controller_Router_Route_Regex(
'(\b.+\-list\b)',
array(
'module' => 'default',
'controller' => 'search',
'action' => 'index'
),
array(
1 => 'productType'
)
);
I can get "car-list" when i want "productType" param. But i cant get rest of the url with $this->_getParam() in controller.
当我想要“productType”参数时,我可以获得“car-list”。但我无法在控制器中使用$ this - > _ getParam()来获取其余的url。
how can i do this? thanks.
我怎样才能做到这一点?谢谢。
1 个解决方案
#1
5
Well, i don't see how to make it with Router_Route_Regex, but with Router_Route it would be easier (thought, i replace "-" with "/")
好吧,我没有看到如何使用Router_Route_Regex,但使用Router_Route它会更容易(想想,我用“/”替换“ - ”)
$categoryRoute = new Zend_Controller_Router_Route
':car/list/*',
array(
'module' => 'default',
'controller' => 'search',
'action' => 'index'
)
);
magic happens due to the "/*" at the end of the string. :car variable can be got with $request->getParam('car');
由于字符串末尾的“/ *”而发生魔术。 :car变量可以用$ request-> getParam('car')获得;
#1
5
Well, i don't see how to make it with Router_Route_Regex, but with Router_Route it would be easier (thought, i replace "-" with "/")
好吧,我没有看到如何使用Router_Route_Regex,但使用Router_Route它会更容易(想想,我用“/”替换“ - ”)
$categoryRoute = new Zend_Controller_Router_Route
':car/list/*',
array(
'module' => 'default',
'controller' => 'search',
'action' => 'index'
)
);
magic happens due to the "/*" at the end of the string. :car variable can be got with $request->getParam('car');
由于字符串末尾的“/ *”而发生魔术。 :car变量可以用$ request-> getParam('car')获得;