本文实例讲述了python定时执行指定函数的方法。分享给大家供大家参考。具体实现方法如下：
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# time a function using time.time() and the a @ function decorator
# tested with Python24 vegaseat 21aug2005
import time
def print_timing(func):
def wrapper(*arg):
t1 = time.time()
res = func(*arg)
t2 = time.time()
print '%s took %0.3f ms' % (func.func_name, (t2-t1)*1000.0)
return res
return wrapper
# declare the @ decorator just before the function, invokes print_timing()
@print_timing
def getPrimeList(n):
""" returns a list of prime numbers from 2 to < n using a sieve algorithm"""
if n < 2: return []
if n == 2: return [2]
# do only odd numbers starting at 3
s = range(3, n+1, 2)
# n**0.5 may be slightly faster than math.sqrt(n)
mroot = n ** 0.5
half = len(s)
i = 0
m = 3
while m <= mroot:
if s[i]:
j = (m*m-3)//2
s[j] = 0
while j < half:
s[j] = 0
j += m
i = i+1
m = 2*i+3
return [2]+[x for x in s if x]
if __name__ == "__main__":
print "prime numbers from 2 to <10,000,000 using a sieve algorithm"
primeList = getPrimeList(10000000)
time.sleep(2.5)
"""
my output -->
prime numbers from 2 to <10,000,000 using a sieve algorithm
getPrimeList took 4750.000 ms
"""
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希望本文所述对大家的Python程序设计有所帮助。