Just a simple question.
只是一个简单的问题。
I have an array:
我有一个数组:
array=("1 2 3" "4 5 6")
If I do:
如果我做:
echo ${array[0]}
echo ${array[1]}
1 2 3 or 4 5 6 will be shown.
将显示1 2 3或4 5 6。
However, if I do:
但是,如果我这样做:
for iter in ${array[@]}
do
echo $iter
done
The shown value is not as I expected.... Can anyone give me the right way to use it?
显示的值并不像我预期的那样....任何人都可以给我正确的使用方法吗?
1 个解决方案
#1
4
Quotation is what you need:
报价是你需要的:
for iter in "${array[@]}"; do
echo "$iter"
done
#1
4
Quotation is what you need:
报价是你需要的:
for iter in "${array[@]}"; do
echo "$iter"
done