![[leetcode]Valid Palindrome @ Python [leetcode]Valid Palindrome @ Python](https://image.shishitao.com:8440/aHR0cHM6Ly9ia3FzaW1nLmlrYWZhbi5jb20vdXBsb2FkL2NoYXRncHQtcy5wbmc%2FIQ%3D%3D.png?!?w=700&webp=1)
原题地址:https://oj.leetcode.com/problems/valid-palindrome/
题意:
Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.
For example,"A man, a plan, a canal: Panama"
is a palindrome."race a car"
is not a palindrome.
Note:
Have you consider that the string might be empty? This is a good question to ask during an interview.
For the purpose of this problem, we define empty string as valid palindrome.
解题思路:将不是字母的字符去掉,然后转换成小写,然后简单的回文判断。
代码:
class Solution:
# @param s, a string
# @return a boolean
def isPalindrome(self, s):
if s == '':
return True
else:
sTmp = ''
for i in range(0, len(s)):
if s[i] >= 'a' and s[i] <= 'z' or s[i] >= '' and s[i] <= '' or s[i] >= 'A' and s[i] <= 'Z':
sTmp += s[i]
sTmp = sTmp.lower()
for i in range(0, len(sTmp)/2):
if sTmp[i] != sTmp[len(sTmp)-1-i]:
return False
return True