在新文件111.pbxml环境中，查看环境变量，发现有几处还是原来的变量名和路径名，是否需要修改？怎样修改，最好能说具体些
或者说，大家工作进展到一定阶段后，是如何备份.pbxml工程文件的？
4 个解决方案
#1
顶一下
#2
用CEImageDiff,将当前工程制作成模板.
#3
谢谢楼上
#4
/* helper routine that does the main job. */
static void __cdecl xtoa (
unsigned long val,
char *buf,
unsigned radix,
int is_neg
)
{
char *p; /* pointer to traverse string */
char *firstdig; /* pointer to first digit */
char temp; /* temp char */
unsigned digval; /* value of digit */
p = buf;
if (is_neg) {
/* negative, so output '-' and negate */
*p++ = '-';
val = (unsigned long)(-(long)val);
}
firstdig = p; /* save pointer to first digit */
do {
digval = (unsigned) (val % radix);
val /= radix; /* get next digit */
/* convert to ascii and store */
if (digval > 9)
*p++ = (char) (digval - 10 + 'a'); /* a letter */
else
*p++ = (char) (digval + '0'); /* a digit */
} while (val > 0);
/* We now have the digit of the number in the buffer, but in reverse
order. Thus we reverse them now. */
*p-- = '\0'; /* terminate string; p points to last digit */
do {
temp = *p;
*p = *firstdig;
*firstdig = temp; /* swap *p and *firstdig */
--p;
++firstdig; /* advance to next two digits */
} while (firstdig < p); /* repeat until halfway */
}
char * __cdecl _itoa (
int val,
char *buf,
int radix
)
{
if (radix == 10 && val < 0)
xtoa((unsigned long)val, buf, radix, 1);
else
xtoa((unsigned long)(unsigned int)val, buf, radix, 0);
return buf;
}
static void __cdecl xtoa (
unsigned long val,
char *buf,
unsigned radix,
int is_neg
)
{
char *p; /* pointer to traverse string */
char *firstdig; /* pointer to first digit */
char temp; /* temp char */
unsigned digval; /* value of digit */
p = buf;
if (is_neg) {
/* negative, so output '-' and negate */
*p++ = '-';
val = (unsigned long)(-(long)val);
}
firstdig = p; /* save pointer to first digit */
do {
digval = (unsigned) (val % radix);
val /= radix; /* get next digit */
/* convert to ascii and store */
if (digval > 9)
*p++ = (char) (digval - 10 + 'a'); /* a letter */
else
*p++ = (char) (digval + '0'); /* a digit */
} while (val > 0);
/* We now have the digit of the number in the buffer, but in reverse
order. Thus we reverse them now. */
*p-- = '\0'; /* terminate string; p points to last digit */
do {
temp = *p;
*p = *firstdig;
*firstdig = temp; /* swap *p and *firstdig */
--p;
++firstdig; /* advance to next two digits */
} while (firstdig < p); /* repeat until halfway */
}
char * __cdecl _itoa (
int val,
char *buf,
int radix
)
{
if (radix == 10 && val < 0)
xtoa((unsigned long)val, buf, radix, 1);
else
xtoa((unsigned long)(unsigned int)val, buf, radix, 0);
return buf;
}
#1
顶一下
#2
用CEImageDiff,将当前工程制作成模板.
#3
谢谢楼上
#4
/* helper routine that does the main job. */
static void __cdecl xtoa (
unsigned long val,
char *buf,
unsigned radix,
int is_neg
)
{
char *p; /* pointer to traverse string */
char *firstdig; /* pointer to first digit */
char temp; /* temp char */
unsigned digval; /* value of digit */
p = buf;
if (is_neg) {
/* negative, so output '-' and negate */
*p++ = '-';
val = (unsigned long)(-(long)val);
}
firstdig = p; /* save pointer to first digit */
do {
digval = (unsigned) (val % radix);
val /= radix; /* get next digit */
/* convert to ascii and store */
if (digval > 9)
*p++ = (char) (digval - 10 + 'a'); /* a letter */
else
*p++ = (char) (digval + '0'); /* a digit */
} while (val > 0);
/* We now have the digit of the number in the buffer, but in reverse
order. Thus we reverse them now. */
*p-- = '\0'; /* terminate string; p points to last digit */
do {
temp = *p;
*p = *firstdig;
*firstdig = temp; /* swap *p and *firstdig */
--p;
++firstdig; /* advance to next two digits */
} while (firstdig < p); /* repeat until halfway */
}
char * __cdecl _itoa (
int val,
char *buf,
int radix
)
{
if (radix == 10 && val < 0)
xtoa((unsigned long)val, buf, radix, 1);
else
xtoa((unsigned long)(unsigned int)val, buf, radix, 0);
return buf;
}
static void __cdecl xtoa (
unsigned long val,
char *buf,
unsigned radix,
int is_neg
)
{
char *p; /* pointer to traverse string */
char *firstdig; /* pointer to first digit */
char temp; /* temp char */
unsigned digval; /* value of digit */
p = buf;
if (is_neg) {
/* negative, so output '-' and negate */
*p++ = '-';
val = (unsigned long)(-(long)val);
}
firstdig = p; /* save pointer to first digit */
do {
digval = (unsigned) (val % radix);
val /= radix; /* get next digit */
/* convert to ascii and store */
if (digval > 9)
*p++ = (char) (digval - 10 + 'a'); /* a letter */
else
*p++ = (char) (digval + '0'); /* a digit */
} while (val > 0);
/* We now have the digit of the number in the buffer, but in reverse
order. Thus we reverse them now. */
*p-- = '\0'; /* terminate string; p points to last digit */
do {
temp = *p;
*p = *firstdig;
*firstdig = temp; /* swap *p and *firstdig */
--p;
++firstdig; /* advance to next two digits */
} while (firstdig < p); /* repeat until halfway */
}
char * __cdecl _itoa (
int val,
char *buf,
int radix
)
{
if (radix == 10 && val < 0)
xtoa((unsigned long)val, buf, radix, 1);
else
xtoa((unsigned long)(unsigned int)val, buf, radix, 0);
return buf;
}