首先是写一个分割字符串的函数,返回table类型
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
|
CREATE OR REPLACE FUNCTION fn_split (p_str IN VARCHAR2, p_delimiter IN VARCHAR2)
RETURN ty_str_split
IS
j INT := 0;
i INT := 1;
len INT := 0;
len1 INT := 0;
str VARCHAR2 (4000);
str_split ty_str_split := ty_str_split ();
BEGIN
len := LENGTH (p_str);
len1 := LENGTH (p_delimiter);
WHILE j < len
LOOP
j := INSTR (p_str, p_delimiter, i);
IF j = 0
THEN
j := len;
str := SUBSTR (p_str, i);
str_split.EXTEND;
str_split (str_split. COUNT ) := str;
IF i >= len
THEN
EXIT;
END IF;
ELSE
str := SUBSTR (p_str, i, j - i);
i := j + len1;
str_split.EXTEND;
str_split (str_split. COUNT ) := str;
END IF;
END LOOP;
RETURN str_split;
END fn_split;
|
上面这个函数可以将字符串分割返回table
1
2
3
4
5
6
7
8
9
10
11
|
create or replace function fn_ispng(
strpng in varchar2
) return number is
v_num number;
begin
WITH t1 AS
( select * from table (fn_split(strpng, '.' ))
)
select count (1) into v_num from t1 where t1.column_value in ( 'png' , 'jpg' , 'jpeg' , 'gif' , 'bmp' , 'eps' );
return v_num;
end fn_ispng;
|
上面这个是判断是否是图片格式,的图片格式返回1
1
|
select fn_ispng( 'dfdfd.png' ) from dual;
|
以上所述是小编给大家介绍的oracle 函数判断字符串是否包含图片格式,希望对大家有所帮助,如果大家有任何疑问请给我留言,小编会及时回复大家的。在此也非常感谢大家对服务器之家网站的支持!
原文链接:http://www.cnblogs.com/lovehersister/archive/2017/07/13/7163167.html