-- ============================================================================= -- Title: 在SQL中分类合并数据行 -- Author: dobear Mail(MSN): dobear_0922@hotmail.com -- Environment: Vista + SQL2005 -- Date: 2008-04-22 -- ============================================================================= --1. 创建表,添加测试数据 CREATETABLE tb(id int, [value]varchar(10)) INSERT tb SELECT1, 'aa' UNIONALLSELECT1, 'bb' UNIONALLSELECT2, 'aaa' UNIONALLSELECT2, 'bbb' UNIONALLSELECT2, 'ccc' --SELECT * FROM tb /**//* id value ----------- ---------- 1 aa 1 bb 2 aaa 2 bbb 2 ccc (5 row(s) affected) */ --2 在SQL2000只能用自定义函数实现 ----2.1 创建合并函数fn_strSum,根据id合并value值 GO CREATEFUNCTION dbo.fn_strSum(@idint) RETURNSvarchar(8000) AS BEGIN DECLARE@valuesvarchar(8000) SET@values='' SELECT@values=@values+','+ value FROM tb WHERE id=@id RETURNSTUFF(@values, 1, 1, '') END GO -- 调用函数 SELECT id, VALUE = dbo.fn_strSum(id) FROM tb GROUPBY id DROPFUNCTION dbo.fn_strSum ----2.2 创建合并函数fn_strSum2,根据id合并value值 GO CREATEFUNCTION dbo.fn_strSum2(@idint) RETURNSvarchar(8000) AS BEGIN DECLARE@valuesvarchar(8000) SELECT@values=isnull(@values+',', '') + value FROM tb WHERE id=@id RETURN@values END GO -- 调用函数 SELECT id, VALUE = dbo.fn_strSum2(id) FROM tb GROUPBY id DROPFUNCTION dbo.fn_strSum2 --3 在SQL2005中的新解法 ----3.1 使用OUTER APPLY SELECT* FROM (SELECTDISTINCT id FROM tb) A OUTER APPLY( SELECT[values]=STUFF(REPLACE(REPLACE( ( SELECT value FROM tb N WHERE id = A.id FOR XML AUTO ), '<N value="', ','), '"/>', ''), 1, 1, '') )N ----3.2 使用XML SELECT id, [values]=STUFF((SELECT','+[value]FROM tb t WHERE id=tb.id FOR XML PATH('')), 1, 1, '') FROM tb GROUPBY id --4 删除测试表tb droptable tb /**//* id values ----------- -------------------- 1 aa,bb 2 aaa,bbb,ccc (2 row(s) affected) */