Given a non-negative integer num
, repeatedly add all its digits until the result has only one digit.
Example:
Input:38
Output: 2
Explanation: The process is like:3 + 8 = 11
,1 + 1 = 2
.
Since2
has only one digit, return it.
Follow up:
Could you do it without any loop/recursion in O(1) runtime?
class Solution(object):
def addDigits(self, num):
"""
:type num: int
:rtype: int
"""
s=str(num)
while len(s)>1:
n=0
for i in s:
n+=int(i)
s=str(n) return int(s)