There are n people (excluding myself) in my 30th birthday party. They sing the traditional "happy birthday" song:
Happy birthday to you! Happy birthday to you! Happy birthday to Rujia! Happy birthday to you!!!
Since I love music, I want to hear something more interesting, not that everyone sings together. Ah yes, I want one person to sing one word!
For example, there are three people: Mom, Dad, Girlfriend, I'd like them to sing like this:
Mom: Happy
Dad: birthday
Girlfriend: to
Mom: you
Dad: Happy
Girlfriend: birthday
Mom: to
Dad: you
Girlfriend: Happy
Mom: birthday
Dad: to
Girlfriend: Rujia
Mom: Happy
Dad: birthday
Girlfriend: to
Mom: you
Very nice, right? What if there are more than 16 people? That's easy: repeat the song until everyone has sung at least once :)
Please, don't stop in the middle of the song.
Input
There is only one test case. The first line contains a single integer n (1<=n<=100). Then each of the next n lines contains a capitalized name (i.e. one upper-case letter followed by zero or more lower-case letters). Each name contains at most 100 characters and do not have whitespace characters inside.
Output
Output the song, formatted as above.
Sample Input
3
Mom
Dad
Girlfriend
Output for the Sample Input
Mom: Happy
Dad: birthday
Girlfriend: to
Mom: you
Dad: Happy
Girlfriend: birthday
Mom: to
Dad: you
Girlfriend: Happy
Mom: birthday
Dad: to
Girlfriend: Rujia
Mom: Happy
Dad: birthday
Girlfriend: to
Mom: you
Rujia Liu's Present 6: Happy 30th Birthday to Myself
Special Thanks: All of you, for participating in this contest; Mom and Dad, for giving birth to me :)
题意很简单，就是N个人，没人唱一次歌词，如果人数多于16，则重复
#include <stdio.h>
#include <string.h>
#include <algorithm>
using namespace std; char name[105][105];
char song[16][16] = {"Happy","birthday","to","you","Happy","birthday","to","you","Happy","birthday","to","Rujia","Happy","birthday","to","you"}; int main()
{
int n,i,j,k;
while(~scanf("%d",&n))
{
for(i = 0; i<n; i++)
scanf("%s",name[i]);
k = n/16;
if(n%16)
k++;
for(i = 0; i<16*k; i++)
printf("%s: %s\n",name[i%n],song[i%16]);
} return 0;
}