如何使用jQuery以秒为单位获得两个时间戳之间的时差？

I want to display x seconds ago based on a MySQL Timestamp.

我想基于MySQL时间戳显示x秒前。

I found the plugin called timeago

我找到了名为timeago的插件

But I cannot find a way to make it display only seconds.

但我找不到让它只显示秒的方法。

I'm OK with 61 seconds, or 300 seconds. Any way to convert the output to seconds with timeago, or with pure jQuery / JavaScript ?

61秒或300秒我没问题。有没有办法使用timeago或纯jQuery / JavaScript将输出转换为秒?

Thanks for any help !

谢谢你的帮助 !

Edit:

Sample Case :

示例案例:

$time1 = "2014-02-02 23:54:04"; // plus PHP ways to format it.
//$time2 = NOW() , or date(); whatever.

I just want to get how many seconds since $time1.

我只想得到自$ time1以来的秒数。

Edit 2:

Working code :

工作代码:

<script type="text/javascript">
$(function(){
    var d2 = new Date();
    var d1 = new Date("2014-02-02 23:54:04");
    $("a#timedif").html("Diff. Seconds : "+((d2-d1)/100).toString());
    // note that you may want to round the value
});
</script>

It outputs Diff. Seconds : NaN

它输出Diff。秒:NaN

4 个解决方案

#1

assuming you parse the string into JavaScript date object, you can do (date2 - date1)/1000

假设您将字符串解析为JavaScript日期对象,则可以执行(date2 - date1)/ 1000

to parse mysql format timestamp, just feed the string into new Date():

解析mysql格式的时间戳,只需将字符串输入新的Date():

 var d2 = new Date('2038-01-19 03:14:07');
 var d1 = new Date('2038-01-19 03:10:07');

 var seconds =  (d2- d1)/1000;

fix of edit 2 in the question:

修复了问题中的编辑2:

<script type="text/javascript">
$(function(){
var d2 = new Date();
var d1 = new Date("2014-02-02 23:54:04");
$("a#timedif").html("Diff. Seconds : "+((d2-d1)/1000).toString());
 });

#2

If you are okay with that plugin you can modify it a little bit to work with seconds only

如果您对该插件没问题,可以稍微修改它以仅使用秒

  var words = seconds < 45 && substitute($l.seconds, Math.round(seconds)) ||
    seconds < 90 && substitute($l.minute, 1) ||
    minutes < 45 && substitute($l.minutes, Math.round(minutes)) ||
    minutes < 90 && substitute($l.hour, 1) ||
    hours < 24 && substitute($l.hours, Math.round(hours)) ||
    hours < 42 && substitute($l.day, 1) ||
    days < 30 && substitute($l.days, Math.round(days)) ||
    days < 45 && substitute($l.month, 1) ||
    days < 365 && substitute($l.months, Math.round(days / 30)) ||
    years < 1.5 && substitute($l.year, 1) ||
    substitute($l.years, Math.round(years));

with this part, go only with converting to seconds

使用此部分,只需转换为秒

see the fiddle: http://jsfiddle.net/zGXLU/1/

看到小提琴:http://jsfiddle.net/zGXLU/1/

#3

jQuery is just a JavaScript library so JavaScript will just work within your jQuery script:

jQuery只是一个JavaScript库,所以JavaScript只能在你的jQuery脚本中运行:

// specified date:
var oneDate = new Date("November 02, 2017 06:00:00");

// number of milliseconds since midnight Jan 1 1970 till specified date
var oneDateMiliseconds = oneDate.getTime();

// number of milliseconds since midnight Jan 1 1970 till now
var currentMiliseconds = Date.now(); 

// return time difference in milliseconds
var timePassedInMilliseconds = (currentMiliseconds-oneDateMiliseconds)/1000;
alert(timePassedInMilliseconds);

#4

My working with time difference for calculating each value separately

我使用时差来分别计算每个值

var start = new Date('Mon Jul 30 2018 19:35:35 GMT+0500');
var end = new Date('Mon Jul 30 2018 21:15:00 GMT+0500');

var hrs = end.getHours() - start.getHours();
var min = end.getMinutes() - start.getMinutes(); 
var sec = end.getSeconds() - start.getSeconds();  

var hour_carry = 0;
var minutes_carry = 0;
if(min < 0){
       min += 60;
       hour_carry += 1;
   }
hrs = hrs - hour_carry;
if(sec < 0){
       sec += 60;
       minutes_carry += 1;
   }

min = min - minutes_carry;

console.log("hrs",hrs);
console.log("min",min);
console.log("sec",sec);
console.log(hrs + "hrs " + min +"min " + sec + "sec");

#1