Android获取设备唯一码

时间:2021-01-04 18:02:54

String uuid = "";
        String serial = null;

        String m_szDevIDShort = "35"  
                Build.BOARD.length() % 10   Build.BRAND.length() % 10  

                Build.CPU_ABI.length() % 10   Build.DEVICE.length() % 10  

                Build.DISPLAY.length() % 10   Build.HOST.length() % 10  

                Build.ID.length() % 10   Build.MANUFACTURER.length() % 10  

                Build.MODEL.length() % 10   Build.PRODUCT.length() % 10  

                Build.TAGS.length() % 10   Build.TYPE.length() % 10  

                Build.USER.length() % 10; //13 位

        try {
            serial = android.os.Build.class.getField("SERIAL").get(null).toString();
            //API>=9 使用serial号
            uuid = new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
        } catch (Exception exception) {
            //serial需要一个初始化
            serial = "serial"; // 随便一个初始化
            //使用硬件信息拼凑出来的15位号码
            uuid = new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();
        }

转自:https://blog.csdn.net/u014031072/article/details/70257907