结论是:
多线程下如果其中一个线程崩溃了会导致其他线程(整个进程)都崩溃;
多进程下如果其中一个进程崩溃了对其余进程没有影响;
多线程
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#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <pthread.h>
#include <assert.h>
void *fun1( void *arg)
{
printf ( "fun1 enter\n" );
while (1)
{
printf ( "%s\n" , __FUNCTION__);
usleep(1000 * 1000);
}
printf ( "fun1 exit\n" );
return (( void *)1);
}
void *fun2( void *arg)
{
printf ( "fun1 enter\n" );
usleep(1000 * 3000);
char * ptr = ( char *) malloc ( sizeof ( char ));
printf ( "ptr1: 0x%x\n" , ptr);
ptr = NULL;
printf ( "ptr2: 0x%x\n" , ptr);
free (ptr);
memcpy (ptr, "123" , 3);
printf ( "ptr3: 0x%x\n" , ptr);
printf ( "fun2 exit\n" );
return (( void *)2);
}
int main( void )
{
pthread_t tid1, tid2;
int err;
err = pthread_create(&tid1, NULL, fun1, NULL);
assert (0 == err);
err = pthread_create(&tid2, NULL, fun2, NULL);
assert (0 == err);
printf ( "main join ...\n" );
// getchar();
pthread_join(tid1, NULL);
pthread_join(tid2, NULL);
return 0;
}
|
多进程
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#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <pthread.h>
#include <assert.h>
void fun( void *arg)
{
printf ( "fun1 enter\n" );
usleep(1000 * 3000);
char * ptr = ( char *) malloc ( sizeof ( char ));
printf ( "ptr1: 0x%x\n" , ptr);
ptr = NULL;
printf ( "ptr2: 0x%x\n" , ptr);
free (ptr);
memcpy (ptr, "123" , 3);
printf ( "ptr3: 0x%x\n" , ptr);
printf ( "fun2 exit\n" );
return ;
}
int main( int argc, char *argv[])
{
assert (2 == argc);
pid_t pid;
int i;
for (i=0; i< atoi (argv[1]); i++)
{
pid = fork();
if (0 > pid)
{
printf ( "fork error" );
exit (1);
}
else if (0 == pid)
{
printf ( "child pid is %lu\n" , (unsigned long )getpid());
fun(NULL);
exit (0);
}
}
printf ( "parent pid is %lu\n" , (unsigned long )getpid());
while (-1 != wait(NULL)); //等待所有子进程结束
printf ( "main return\n" );
getchar ();
return 0;
}
|
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原文链接:https://segmentfault.com/a/1190000022828326