具有多个定义的.NET Enum类型

Imagine this enumerate:

想象一下这个枚举：

public enum eMyEnum
{
    cValue1 = 0,
    cValue2 = 1,
    cValue2_too = 1,
    cValue3 = 5
}

Is there a way to iterate over all the values (not the labels)? If I try

有没有办法迭代所有的值（而不是标签）？如果我试试

var values = typeof(eMyEnum).GetEnumValues();

I end up with {cValue1,cValue2,cValue2,cValue3}, while I'm looking for a way to retrieve {cValue1,cValue2,cValue3}. Note: I intentionally left a gap between 1 and 5.

我最终得到{cValue1，cValue2，cValue2，cValue3}，而我正在寻找一种方法来检索{cValue1，cValue2，cValue3}。注意：我故意留下1到5之间的差距。

3 个解决方案

#1

This is the VB.NET Syntax if anybody is interested:

这是VB.NET语法，如果有人感兴趣：

[Enum].GetValues(GetType(eMyEnum)).Cast(of eMyEnum).Distinct

要么

GetType(eMyEnum).GetEnumValues().Cast(of eMyEnum).Distinct

so this should be the C# version (cannot test):

所以这应该是C＃版本（无法测试）：

Enum.GetValues(typeof(eMyEnum)).Cast<eMyEnum>().Distinct

要么

typeof(eMyEnum).GetEnumValues().Cast<eMyEnum>().Distinct

#2

This should work:

这应该工作：

var values = typeof(eMyEnum).GetEnumValues().Select(v => (int)v).Distinct();

#3

Linq could come to rescue for this:

Linq可以为此解救：

IEnumerable<eMyEnum> values = typeof(eMyEnum).GetEnumValues()
                               .Cast<int>().Distinct().Cast<eMyEnum>();

Note that this will get you only cValue2 and not cValue2_too i think.

请注意，我认为这只会让你获得cValue2而不是cValue2_too。

#1