获得错误C2177: MPIR的常量太大

Running on Widows 7 with MSVS 2010

使用MSVS 2010的寡妇7

I am following this tutorial to understand how to use MPIR library for adding two big integers

我将通过本教程了解如何使用MPIR库来添加两个大整数

I understand this library should help me in adding very big numbers as shown in the program below:

我明白这个图书馆应该帮助我增加非常大的数字，如下图所示:

#include < stdio.h>
#include < stdlib.h>
#include < gmpxx.h>
#include < iostream>

using namespace std;

void main(int argc, char *argv[])
{

   mpz_class answer_a = 111111111111111111111111111111111111111111111111;
   mpz_class answer_b = 111111111111111111111111111111111111111111111111;


   mpz_class answer_c; 

   answer_c= answer_b + answer_a ;   

   cout << answer_c<<"\n";


}

But still I get error C2177: constant too big. Did I misunderstand MPIR ?

但我还是会得到错误C2177:常数太大。我是否误解了MPIR ?

1 个解决方案

#1

Such constant is (very likely) too big for standard integer types. You should use char * constructor instead:

对于标准整数类型来说，这样的常量(很可能)太大了。你应该使用char *构造函数代替:

void mpz_class::mpz_class (const char *s)

For example:

例如:

mpz_class answer_a("111111111111111111111111111111111111111111111111");

to make this work you need to include suitable MPIR C++ interface header (notice that <gmpxx.h> is from C++ interface of GNU MP library):

要完成这项工作，您需要包含合适的MPIR c++接口头(请注意来自GNU MP library的c++接口): 。h>

#include <mpirxx.h>

# include < mpirxx.h >

See 12.2 C++ Interface Integers chapter in MPIR documentation for more details.

有关更多细节，请参阅MPIR文档中的12.2 c++接口整数章节。

#1