Consider the following code:
请考虑以下代码：
var x = 32;
The number 32 will fit in within sbyte, byte, short, ushort, etc.
数字32将适合sbyte，byte，short，ushort等。
Why does .NET assume this is an int?
为什么.NET假设这是一个int？
Same question for var x = 3.2; .NET assumes double
var x = 3.2的相同问题; .NET假定为double
1 个解决方案
#1
4
Why does .NET assume this is an int?
为什么.NET假设这是一个int？
Wrong question/subject. It is the C# compiler that assume this is an int.
错误的问题/主题。 C＃编译器假设这是一个int。
Taken from 2.4.4.2 Integer literals:
取自2.4.4.2整数文字：
The type of an integer literal is determined as follows:
If the literal has no suffix, it has the first of these types in which its value can be represented: int, uint, long, ulong.整数文字的类型确定如下：如果文字没有后缀，则它具有这些类型中的第一个，其值可以表示为：int，uint，long，ulong。
and from 2.4.4.3 Real literals:
从2.4.4.3真正的文字：
If no real type suffix is specified, the type of the real literal is double.
如果未指定实际类型后缀，则实数的类型为double。
Another important "trick" of the compiler, that makes this legal:
编译器的另一个重要“技巧”，使这合法：
byte b = 5;
(normally 5 would be an int, and there is no implicit conversion from int to byte), but:
（通常5将是一个int，并且没有从int到byte的隐式转换），但是：
Taken from 6.1.6 Implicit constant expression conversions:
取自6.1.6隐式常量表达式转换：
An implicit constant expression conversion permits the following conversions:
隐式常量表达式转换允许以下转换：
A constant-expression (Section 7.15) of type int can be converted to type sbyte, byte, short, ushort, uint, or ulong, provided the value of the constant-expression is within the range of the destination type.
如果constant-expression的值在目标类型的范围内，则int类型的常量表达式（第7.15节）可以转换为sbyte，byte，short，ushort，uint或ulong类型。
A constant-expression of type long can be converted to type ulong, provided the value of the constant-expression is not negative.
如果constant-expression的值不是负数，则long类型的常量表达式可以转换为ulong类型。
#1
4
Why does .NET assume this is an int?
为什么.NET假设这是一个int？
Wrong question/subject. It is the C# compiler that assume this is an int.
错误的问题/主题。 C＃编译器假设这是一个int。
Taken from 2.4.4.2 Integer literals:
取自2.4.4.2整数文字：
The type of an integer literal is determined as follows:
If the literal has no suffix, it has the first of these types in which its value can be represented: int, uint, long, ulong.整数文字的类型确定如下：如果文字没有后缀，则它具有这些类型中的第一个，其值可以表示为：int，uint，long，ulong。
and from 2.4.4.3 Real literals:
从2.4.4.3真正的文字：
If no real type suffix is specified, the type of the real literal is double.
如果未指定实际类型后缀，则实数的类型为double。
Another important "trick" of the compiler, that makes this legal:
编译器的另一个重要“技巧”，使这合法：
byte b = 5;
(normally 5 would be an int, and there is no implicit conversion from int to byte), but:
（通常5将是一个int，并且没有从int到byte的隐式转换），但是：
Taken from 6.1.6 Implicit constant expression conversions:
取自6.1.6隐式常量表达式转换：
An implicit constant expression conversion permits the following conversions:
隐式常量表达式转换允许以下转换：
A constant-expression (Section 7.15) of type int can be converted to type sbyte, byte, short, ushort, uint, or ulong, provided the value of the constant-expression is within the range of the destination type.
如果constant-expression的值在目标类型的范围内，则int类型的常量表达式（第7.15节）可以转换为sbyte，byte，short，ushort，uint或ulong类型。
A constant-expression of type long can be converted to type ulong, provided the value of the constant-expression is not negative.
如果constant-expression的值不是负数，则long类型的常量表达式可以转换为ulong类型。