如何在ruby中对数组进行排序

I have a following array

我有一个以下数组

arr = ["2014-05-02T19-49-55_1280x720_vga2usb.mp4", "2014-05-02T19-49-55_544x288_left_cam.mp4", "2014-05-02T19-49-55_544x288_right_cam.mp4", "2014-05-02T19-49-55_1632x288.mp4"]

I need to sort this array in a way that I get following:

我需要按照以下方式对此数组进行排序：

["2014-05-02T19-49-55_1632x288.mp4", "2014-05-02T19-49-55_544x288_left_cam.mp4", "2014-05-02T19-49-55_544x288_right_cam.mp4", "2014-05-02T19-49-55_1280x720_vga2usb.mp4"]

I tried to use the sort method arr.sort and arr.sort_by{|word| word.downcase} But it is giving me output as

我尝试使用sort方法arr.sort和arr.sort_by {| word | word.downcase}但它给我的输出为

["2014-05-02T19-49-55_1280x720_vga2usb.mp4", "2014-05-02T19-49-55_1632x288.mp4", "2014-05-02T19-49-55_544x288_left_cam.mp4", "2014-05-02T19-49-55_544x288_right_cam.mp4"]

How can I do this?

我怎样才能做到这一点？

1 个解决方案

#1

Try to use sort like this:

尝试使用这样的排序：

arr.sort { |x,y| y <=> x }

If you need to sort by substring try something like this:

如果你需要按子串排序尝试这样的事情：

arr.sort { |x,y| y[m,n] <=> x[m,n]}

EDIT: this should work:

编辑：这应该工作：

arr.sort do |x,y| 
    regex = /x[[:digit:]]+(.+?)$/
    regex.match(x)[1] <=> regex.match(y)[1]
end

#1