i have a table like this
我有一张这样的桌子
在此处输入图像描述
2 个解决方案
#1
0
this will return you number of records in a table:
这将返回表中的记录数:
select count(*) from tablename;
#2
0
SELECT
base.*, aaa.the_count
FROM
TABLE base
INNER JOIN (
SELECT
GROUP,
count(*) AS the_count
FROM
TABLE
GROUP BY
1
) aaa ON aaa. GROUP = base. GROUP
#1
0
this will return you number of records in a table:
这将返回表中的记录数:
select count(*) from tablename;
#2
0
SELECT
base.*, aaa.the_count
FROM
TABLE base
INNER JOIN (
SELECT
GROUP,
count(*) AS the_count
FROM
TABLE
GROUP BY
1
) aaa ON aaa. GROUP = base. GROUP