将十六进制字符串转换为十六进制int

I have to convert a hexadecimal string to a hexadecimal integer, like this:

我必须将十六进制字符串转换为十六进制整数，如下所示：

color = "0xFF00FF" #can be any color else, defined by functions
colorto = 0xFF00FF #copy of color, but from string to integer without changes

I can have RGB format too.

我也可以使用RGB格式。

I'm obliged to do this because this function goes after :

我不得不这样做，因为这个功能如下：

def i2s int, len
  i = 1
  out = "".force_encoding('binary')
  max = 127**(len-1)

  while i <= len
    num = int/max
    int -= num*max
    out << (num + 1)
    max /= 127
    i += 1
  end

  out
end

I saw here that hexadecimal integers exist. Can someone help me with this problem?

我在这里看到存在十六进制整数。有人可以帮我解决这个问题吗？

3 个解决方案

#1

You'd need supply integer base argument to String#to_i method:

你需要为String＃to_i方法提供整数基本参数：

irb> color = "0xFF00FF"
irb> color.to_i(16)
=> 16711935
irb> color.to_i(16).to_s(16)
=> "ff00ff"
irb> '%#X' % color.to_i(16)
=> "0XFF00FF"

#2

First off, an integer is never hexadecimal. Every integer has a hexadecimal representation, but that is a string.

首先，整数永远不是十六进制。每个整数都有一个十六进制表示，但这是一个字符串。

To convert a string containing a hexadecimal representation of an integer with the 0x prefix to an integer in Ruby, call the function Integer on it.

要将包含带有0x前缀的整数的十六进制表示形式的字符串转换为Ruby中的整数，请在其上调用函数Integer。

Integer("0x0000FF") # => 255

#3

2.1.0 :402 > "d83d".hex => 55357

2.1.0：402>“d83d”.hex => 55357

#1