直接贴代码:(领悟看个人QAQ)
百度搜的,但是怕忘记。
一张表获取最新的一条记录:
-- 方法1 select a.* from table1 a where not exists(select 1 from table1 b where b.name=a.name and b.gdtime>a.gdtime) -- 方法2 select a.* from table1 a inner join (select name, max(gdtime) 'maxgdtime' from table1 group by name) b on a.name=b.name and a.gdtime=b.maxgdtime
mysql中最大值< max(col) > 与最小值< min(col) >针对字符串的取值不对:
select min(col * 1) , max(col * 1) from table;