Say I have:
说我有：
a = [1, 2, 3]
b = [1, 2, 3]
is there a way to test the lists to see if they are the same, without having to loop through each entry?
有没有办法测试列表，看看它们是否相同，而不必遍历每个条目？
Here's what I was thinking..I know to check if two variables are the same I could use:
这就是我的想法..我知道检查两个变量是否相同我可以使用：
id(a)
but it doesn't work because the ID's are different so is there some type of checksum or way that python stores values of the table so I can simply compare two variables?
但它不起作用，因为ID是不同的，所以有一些类型的校验和或python存储表的值的方式所以我可以简单地比较两个变量？
3 个解决方案
#1
11
Doesn't == work?
不= =工作？
>>> a = [1, 2, 3]
>>> b = [1, 2, 3]
>>> a == b
True
#2
3
the == operator should function as expected on lists
==运算符应该在列表上按预期运行
>>> x = [1, 2]
>>> y = [1, 2]
>>> x == y
True
#3
0
the == operator should function works on lists
==运算符应该在列表上起作用
This output is received on certain versions of python, I don't know which.
这个输出是在某些版本的python上收到的，我不知道哪个。
>>> import numpy as np
>>> x = [1, 2, 3, 4]
>>> y = [1, 2, 3, 4]
>>> z = [1, 2, 2, 4]
>>> x == y
[True, True, True, True]
>>> x == z
[True, True, False, True]
After this, just use numpy to determine the entire list.
在此之后，只需使用numpy来确定整个列表。
>>> np.all(x == y)
True
>>> np.all(x == z)
False
or if only a single similarity is required:
或者如果只需要一个相似性：
>>> np.any(x == z)
True
#1
11
Doesn't == work?
不= =工作？
>>> a = [1, 2, 3]
>>> b = [1, 2, 3]
>>> a == b
True
#2
3
the == operator should function as expected on lists
==运算符应该在列表上按预期运行
>>> x = [1, 2]
>>> y = [1, 2]
>>> x == y
True
#3
0
the == operator should function works on lists
==运算符应该在列表上起作用
This output is received on certain versions of python, I don't know which.
这个输出是在某些版本的python上收到的，我不知道哪个。
>>> import numpy as np
>>> x = [1, 2, 3, 4]
>>> y = [1, 2, 3, 4]
>>> z = [1, 2, 2, 4]
>>> x == y
[True, True, True, True]
>>> x == z
[True, True, False, True]
After this, just use numpy to determine the entire list.
在此之后，只需使用numpy来确定整个列表。
>>> np.all(x == y)
True
>>> np.all(x == z)
False
or if only a single similarity is required:
或者如果只需要一个相似性：
>>> np.any(x == z)
True