I have a JSONObject which had a JSONArray as a value for each key.
我有一个JSONObject,它有一个JSONArray作为每个键的值。
{
"abc" : [null, "1,3", "2,4"],
"dbs" : [null, "1,4", "4,5"],
"sad" : [null, "6,2", "3,4", "5,5"]
}
I want to iterate over the object and take the JSONArray value for each key and put it into a string[]. Example for key: abc i would like to have a String[]: [null, "1,3", "2,4"]
我想迭代对象并为每个键获取JSONArray值并将其放入字符串[]。 key的示例:abc我想要一个String []:[null,“1,3”,“2,4”]
Could some one please help me with this?
有人可以帮我这个吗?
I have tried the following:
我尝试过以下方法:
for (var key in jsonObject) {
if (jsonObject.hasOwnProperty(key)) {
var array = jsonObject[key];
}
}
But this gives me: ",1,3,2,4"
但这给了我:“,1,3,2,4”
1 个解决方案
#1
This should do the trick:
这应该做的伎俩:
function extract(data){
return Object.keys(data).map(function(x){
return data[x].filter(function(z){return z!==null;});
});
}
Here is the fiddle to play with. For explanation of map, take a look at MDN
这是小提琴。有关地图的说明,请查看MDN
If you want to flatten the data, you could extend it to:
如果要展平数据,可以将其扩展为:
function flatten(data){
return Object.keys(Object.keys(data).map(function(x){
return data[x].filter(function(z){return z!==null;});
}).reduce(function(o,n){
n.forEach(function(x){
o[x]=x;
});
return o;
},{}));
}
#1
This should do the trick:
这应该做的伎俩:
function extract(data){
return Object.keys(data).map(function(x){
return data[x].filter(function(z){return z!==null;});
});
}
Here is the fiddle to play with. For explanation of map, take a look at MDN
这是小提琴。有关地图的说明,请查看MDN
If you want to flatten the data, you could extend it to:
如果要展平数据,可以将其扩展为:
function flatten(data){
return Object.keys(Object.keys(data).map(function(x){
return data[x].filter(function(z){return z!==null;});
}).reduce(function(o,n){
n.forEach(function(x){
o[x]=x;
});
return o;
},{}));
}