如何从数组中的散列中获取值?

I have an array consisting of multiple hashes with the same structures. I also have another array filled with strings:

我有一个由多个散列组成的数组，它们具有相同的结构。我还有另一个数组，里面有字符串:

prop_array = [
                {:name=>"item1", :owner=>"block1",:ID=>"11"},
                {:name=>"item2", :owner=>"block2",:ID=>"22"},
                {:name=>"item3", :owner=>"block3",:ID=>"33"},
                {:name=>"item4", :owner=>"block4",:ID=>"44"}
            ]


owner_array = ["block1","block2","block3","block4"]

I want to check if any of the :owner values in the hash matches with any of the strings in owner_array and set the variable :partID to the :ID value:

我想要检查是否有:哈希表中的所有值与owner_array中的任何字符串相匹配，并设置变量:partID到:ID值:

I tried the following but it doesn't work:

我试了一下，但没用:

owner_array.each do |owner|
    prop_array.each do |prop|
        prop.each do |key, value|
            if key[:owner] == owner.to_s
                puts "YES"
                partID = key[:ID]
                puts partID
            end
        end
    end
end

If this ran correctly partID should be returned:

如果正确运行，则返回:

=> "11"
=> "22"
=> "33"
=> "44"

1 个解决方案

#1

I want to check if the any of the ':owner' value in the hash matches with any of the strings in owner_array

我想要检查在哈希表中是否有任何“:owner”值与owner_array中的任何字符串相匹配。

prop_array.select {|hash| owner_array.include?(hash[:owner]) }
#=> [{:name=>"item1", :owner=>"block1", :ID=>"11"}, {:name=>"item2", :owner=>"block2", :ID=>"22"}, {:name=>"item3", :owner=>"block3", :ID=>"33"}, {:name=>"item4", :owner=>"block4", :ID=>"44"}]

set the variable ":partID" to that ':ID' value

设置变量“:partID”到“:ID”值。

 partID = prop_array.select { |hash| owner_array.include?(hash[:owner]) }
                    .map    { |hash| hash[:ID] }
 #=> ["11", "22", "33", "44"]

EDIT

Since you want these values to assign in a loop, go with:

因为您希望这些值在循环中赋值，请使用:

partID = prop_array.select { |hash| owner_array.include?(hash[:owner]) }.each do |hash|
  # assignment happens here one by one
  cell_id = hash[:ID] # or whatever logic you have to assign this ID to cell
end