php将json数组合并为一个数组

时间:2021-08-29 08:36:37

I am trying to loop through some json files, and combine them into one json file. My plan is to have a global $allData array, and just merge new candidates into them.

我试图循环一些json文件,并将它们组合成一个json文件。我的计划是拥有一个全局$ allData数组,并将新候选者合并到它们中。

<?php
$allData = array();
$count = 0;
if ($handle = opendir('./json/')) {
    while (false !== ($entry = readdir($handle))) {
        if ($entry != "." && $entry != "..") {

            echo $entry."<br />";

            $source_file = file_get_contents('./json/'.$entry);

            $data = json_decode($source_file,TRUE);

            if($data != null){


                $allData = array_merge($allData,$data);
                echo "<br /><br /><br /><br /> !!!! <br /><br /><br /><br />";
                print_r($allData);

            }
            else{
                echo "Invalid Json File";
            } //end else            
        }
closedir($handle);
}

echo "<br /><br /><br /><br /> !!!! <br /><br /><br /><br />";

print_r($allData);  

However, the merge is overwriting the file. How can I combine multiple json files into one?

但是,合并将覆盖该文件。如何将多个json文件合并为一个?

I would like the following result:

我想得到以下结果:

1.json:

{"date":"10"},{"comment":"some comment"},{"user":"john"}

2.json:

{"date":"11"},{"comment":"another quote"},{"comment":"jim"}

combined.json

[{"date":"10"},{"comment":"some comment"},{"user":"john"},
{"date":"11"},{"comment":"another quote"},{"comment":"jim"}]

I am only getting one of these values after I merge the arrays.

合并数组后,我只获得其中一个值。

[{"date":"25.4.2013 10:40:10"},{"comment":"some text"},{"comment":"some more text"},
[{"date":"25.4.2013 10:45:15"},{"comment":"another quote"},{"comment":"quote"}]]

2 个解决方案

#1


8  

Your merge is odd:

你的合并是奇怪的:

$result = array_merge($allData,$data);

You want to be merging each new $data array onto a growing $allData array right? I think you want to do this instead:

你想将每个新的$ data数组合并到一个不断增长的$ allData数组上吗?我想你想这样做:

$allData = array_merge($allData,$data);

Also you can get rid of this, it's not necessary.

你也可以摆脱这个,这是没有必要的。

if($count == 0){
    $allData = $data;
}

#2


2  

As stated before, $result = array_merge($allData,$data); is the best way to merge arrays. This code works to merge the two, however, the problem was that my json was not properly formed.

如前所述,$ result = array_merge($ allData,$ data);是合并数组的最佳方法。这段代码可以合并两者,但问题是我的json没有正确形成。

I didn't have [] around my two files, so they could not be merged properly.

我的两个文件周围没有[],因此无法正确合并。

#1


8  

Your merge is odd:

你的合并是奇怪的:

$result = array_merge($allData,$data);

You want to be merging each new $data array onto a growing $allData array right? I think you want to do this instead:

你想将每个新的$ data数组合并到一个不断增长的$ allData数组上吗?我想你想这样做:

$allData = array_merge($allData,$data);

Also you can get rid of this, it's not necessary.

你也可以摆脱这个,这是没有必要的。

if($count == 0){
    $allData = $data;
}

#2


2  

As stated before, $result = array_merge($allData,$data); is the best way to merge arrays. This code works to merge the two, however, the problem was that my json was not properly formed.

如前所述,$ result = array_merge($ allData,$ data);是合并数组的最佳方法。这段代码可以合并两者,但问题是我的json没有正确形成。

I didn't have [] around my two files, so they could not be merged properly.

我的两个文件周围没有[],因此无法正确合并。